Area of a triangle = 0.5*base*height
No. It is not possible, because a triangle cannot have a side longer than the sum of two other sides. 5 is greater than 2+2. Therefore the triangle cannot exist.
2cm*5cm*3cm=30cm3The volume of the cuboid: 2*5*3 = 30 cubic cm
32.56
5cm, 5cm, and 5cm could represent the lengths of the sides of an equilateral triangle, or might indicate the length, width, and height of a cube.
yes it is. When you're dealing with the Pythagorean theory, a 3,4,5 triangle is a special triangle. For example, if a triangle has side lengths of 3cm and 4cm, then you automatically know that the other side length is 5cm. It also works if the side lengths are 5cm and 4cm or 5cm and 3cm.
What is the area of a triangle with base 2cm and height 3cm
In order to find the area of a rectangle, multiply the length by the width of the rectangle. For example: If the length of a rectangle is 5cm and the width of a rectangle is 2cm, then the area of the rectangle would be 5cm X 2cm = 10cm².
Area of a triangle = 1/2 (Base x Height) Example: Width 13cm, Height 5cm, Base 12cm then; Area=1/2(12cm x 5cm) Area=6cm x 5cm Area=30cm2
this is 5cm (:
Area = 0.5*4*5 = 10 square cm
The area of a triangle = 1/2*base*height = 1/2*5*7 = 17.5 cm2.The fact that it is an isosceles triangle is irrelevant.
The area of a rectangle is given by the formula: length x width. So, for the textbook, the area would be 5cm x 2cm = 10 square cm.
The area of a 12cm by 5cm right-angled triangle is: 42 cm2
Any shape you want as long as the area within its boundary is 6cm2.examples:a triangle of base 6 cm and height 2 cm;a rectangle 2cm by 3 cm;an L shaped hexagon with sides 5cm, 2cm, 1cm, 1cm, 4cm, 1cm;circle of radius approx 1.382 cm;
No. It is not possible, because a triangle cannot have a side longer than the sum of two other sides. 5 is greater than 2+2. Therefore the triangle cannot exist.
35/2 cm² 0r 17.5 cm² area = 0.5 x base x height
No because to form a triangle the sum of its smallest sides must be greater than its longest side.