The area of a 12cm by 5cm right-angled triangle is: 42 cm2
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I cut out the lengths to have a visual look at the problem and the answer is NO you cannot arrange 5cm, 12cm, and 19cm into a triangle. Even straightening out the lengths of 5cm and 12cm into a 180 degree angle will not measure out to the 19cm. You cannot have a side that is more than the length of the other two sides combined in a triangle.
a is one of the equal sides of the iscosceles triangle b is the base perimeter is a + a + b = 46cm a = b + 5cm subsitute a for b + 5cm in the perimeter equation b + 5cm + b + 5cm + b = 46cm This simplifies down to 3b + 10cm = 46cm subtract 10cm from both sides of the equation 3b + 10cm - 10cm = 46cm - 10cm 3b = 36cm Then divide each side of the equation by 3 3b ÷ 3 = 36cm ÷ 3 b = 12cm Subsitute b back into a = b +5cm a = 12cm + 5cm a = 17cm So you have 2 sided with the length of 17cm and the base with the length of 12cm
To find the area of a triangle, you can use the formula: Area = 0.5 * base * height. In this case, the base is 5cm and the height is 7cm. Plugging these values into the formula, we get Area = 0.5 * 5cm * 7cm = 17.5 square centimeters. Therefore, the area of the triangle is 17.5 square centimeters.
The surface area is 750 cm^3
For it to be a right angle triangle the 3rd side must be 5cm