Equation of circle: x^2 +y^2 -10x +6y -15 = 0
Completing the squares: (x-5)^2 +(y+3)^2 = 49 square units
Therefore center of circle is at (5, -3) and its radius is 7 units
Centre = (5, -3), radius = 7.
The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1
56
1st circle: x^2 +y^2 -6x +8y -75 = 01st circle: center at (3, -4) and radius 102nd circle: x^2 +y^2 -30x -24y +269 = 02nd circle: center at (15, 12) and radius 10Midpoint of (15, 12) and (3, -4): (9, 4) which is the point of contactProof: distance from (15, 12) to (9, 4) = 10Proof: distance from (3, -4) to (9, 4) = 10
The inner circle is x2 + y2 = 4. The radius of the inner circle is the square root of 4, which is 2. To find the radius of the outer circle, multiply 2 times 4. The radius of the outer circle is 8. Square 8 (82 or 8 x 8) to find the number to put into the equation of the outer circle. This is 64. The equation for the outer circle is x2 + y2 = 64.
Equation of the circle: x^2 +y^2 +4x -6y +10 = 0 Completing the squares: (x+2)^2 +(y-3)^2 = 3 Radius of the circle: square root of 3 Center of circle: (-2, 3) Distance from (0, 0) to (-2, 5) = sq rt of 13 which is the hypotenuse of right triangle. Using Pythagoras' theorem : distance squared - radius squared = 10 Therefore length of tangent line is the square root of 10 Note that the tangent of a circle meets its radius at right angles.
That's the equation of a circle with its center at the origin and a radius of 8.
The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1
Centre = (0,0), the origin; radius = 11
Draw a circle with its center at the origin and a radius of 3.
It is the equation of a circle with radius of 6 and its center at the origin.
The centre is (3,-1) and the radius is sqrt(10).
Radius = 1111
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
The radius will depend on the plus or minus value of 10 or whether or not it needs a plus sign but the center of the circle is at (-2, 3)
x2+y2+4x+2y+3=0(x+2)2 + (Y+2.5)2 = 3This is the equation of circle with center at (-2,-2.5) with radius 3.5
If that equals 16 then the radius is 4
4