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What is the equation of a circle whose diameter's end points are at 2 -3 and 8 7?
The mid point of the diameter is the circle's centre: Mid point of (2, -3) and (8, 7) is ((2 + 8)/2, (-3 + 7)/2) = (5, 2) The radius is half the diameter, but as the equation for a circle requires the radius squared: radius = diameter/2 → radius² = diameter² / 4 Diameter (and diameter²) can be found using Pythagoras: diameter² = change_in_x² + change_in_y² = (8 - 2)² + (7 - -3)² = 6² + 10² = 136 → radius² = 136/4 = 34 Circle with centre (X, Y) and radius r has equation: (x - X)² + (y - Y)² = r² → (x - 5)² + (y - 2)² = 34 → x² -10x + 25 + y² - 4y + 4 = 34 → x² + y² - 10x - 4x - 5 = 0
What is the factorial of 34?
34 factorial = 295,232,799,039,604,140,847,618,609,643,520,000,000.
Prime factorization of 34?
The Prime Factors of 34 are 2, 17
What is 17 divided by 0.5?
34
What is the LCM of 34 and 56?
LCM of 34 and 56 = 952
