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x^2-3x-28=0...................
None because without an equality sign and not knowing the plus or minus values of 3x and 7 it can't be considered to be an equation.
1 is the answer
x2 + 3x - 28 = x2 + 7x - 4x - 28 = x(x + 7) - 4(x + 7) = (x + 7)(x - 4)
(7x + 4) = (3x + 7) Subtract (3x + 4) from both sides of the equation. (7x + 4) - 3x - 4 = (3x + 7) - 3x - 4 4x = 3 x = 3/4 Check: (7x + 4) = 7 (3/4) + 4 = (21/4) + 4 = (21/4) + (16/4) = 37/4 (3x + 7) = 3 (3/4) + 7 = (9/4) + 7 = (9/4) + (28/4) = 37/4 Yay.