5x+y=-7 3x+y=15 8=D
If you mean: y = -3x+7 then the slope is -3 and the y intercept is 7
Standard form is: y = Mx + b so you must solve for y 3x = 2y + 7 3x - 7 = 2y 2y = 3x - 7 y = ( 3 / 2 )x - ( 7 / 2 )
3x + 7y = 14Subtract 3x from each side:7y = -3x + 14Divide each side by 7:y = -3/7 x + 2
x = -3, y = 7
y-3x+6y=12 7y=3x+12 y=3x/7 +12/7
The slope of y is -3x, hope that help
5x+y=-7 3x+y=15 8=D
If you mean: y = -3x+7 then the slope is -3 and the y intercept is 7
3x+2y-7=0 2y=-3x+7 y=1/2(-3x+7) or -3/2 x +7/2
Substitute y = 0 in the equation: 0 = 3x + 7 so that x = -7/3
Standard form is: y = Mx + b so you must solve for y 3x = 2y + 7 3x - 7 = 2y 2y = 3x - 7 y = ( 3 / 2 )x - ( 7 / 2 )
3x + 7y = 14Subtract 3x from each side:7y = -3x + 14Divide each side by 7:y = -3/7 x + 2
No because they don't have the same slope (9x & 3x)
x = -3, y = 7
3x + y = 7 First, turn the equation into the slope-intercept form, y = mx + b, where m is the slope of the graph that that equation represents (solve for y).3x + y = 7 subtract 3x to both sidesy = -3x + 7So you clearly see that the slope is -3.
Where is y in the first equation, you put its equivalent (=) -3x + 11 The first equation is then transformed into: 3x + 2*(-3x + 11) = 7. Then you get: 3x + (-6x) + 2*11 = 7 <=> -3x + 22 = 7 <=> 22 - 7 = 3x <=> 3x = 15 <=> x = 15/3 <=> x = 5. Then you substitute the x in the second equation by its equivalent so, (x = 5) y = -3*x + 11 <=> y = -3*5 + 11 <=> y = -15 + 11 <=> y = -4. x = 5. y = -4.