(a + 4)(a^2 - 4a + 16)
Sum and difference of two cubes is factored this way : a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
Yes and the highest common factor is 32
The factors of 49 are 1, 7, and 49. The factors of 64 are 1, 2, 4, 8, 16, 32, and 64. The only common factor is 1, which means the greatest common factor is also 1.
x^2 - 64.
(3x + 8)(3x - 8)
(a - 1)(a^2 + a + 1)
2a3 - 128 = 2*(a3 - 64) = 2*(a -4)*(a2 + 4a + 16)
Just choose the smaller exponent. The GCF of a3 and a5 is a3
It can be. 64 is a factor of 128, among others.
No, 3 is not a factor of 64.
No, 4 is a factor of 64.
I think you left part the the equation out.... If a = 4, then a3 ÷ a = Well if a=4 then use this example (43 ÷ 4)= (64 ÷ 4)= 16 that's your answer.
The Greatest Common Factor (GCF) of 64 and 128 is: 64
The GCF is 1.
a(a^2 - 9a + 3)
(a - 2)(a^2 + 4)
64 is not a factor of 8.Factor of a number x is always less than or equal to x.