Sum and difference of two cubes is factored this way : a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
Yes and the highest common factor is 32
The number that is a perfect square and has a factor of 32 is 64. A perfect square is a number that can be expressed as the product of an integer multiplied by itself, such as 8 x 8 = 64. Since 32 is a factor of 64, it means that 64 can be divided evenly by 32 without leaving a remainder.
The factors of 49 are 1, 7, and 49. The factors of 64 are 1, 2, 4, 8, 16, 32, and 64. The only common factor is 1, which means the greatest common factor is also 1.
x^2 - 64.
(a - 1)(a^2 + a + 1)
2a3 - 128 = 2*(a3 - 64) = 2*(a -4)*(a2 + 4a + 16)
Just choose the smaller exponent. The GCF of a3 and a5 is a3
It can be. 64 is a factor of 128, among others.
No, 3 is not a factor of 64.
No, 4 is a factor of 64.
I think you left part the the equation out.... If a = 4, then a3 ÷ a = Well if a=4 then use this example (43 ÷ 4)= (64 ÷ 4)= 16 that's your answer.
The Greatest Common Factor (GCF) of 64 and 128 is: 64
The GCF is 1.
a(a^2 - 9a + 3)
(a - 2)(a^2 + 4)
64 is not a factor of 8.Factor of a number x is always less than or equal to x.