The GCF is 12a2b4
Just choose the smaller exponent. The GCF of a3 and a5 is a3
(a - 1)(a^2 + a + 1)
gcd(a,b) = greatest common divisor (or factor, whatever) of a and b. For any set of number, a1, a2, a3, ..., you can use the Euclidean algorithm (http://en.wikipedia.org/wiki/Euclidean_algorithm) to get the gcd(a1, a2), and then again to get gcd(gcd(a1, a2), a3), etc. Often, though, you can eyeball it. So 24*3 = 72. Therefore, gcd(24, 72)=24. 24 does not divide 132, but 12 does (the next biggest factor of 24), so gcd(24, 72, 132)=12.
Go to cell D3 and enter the following: "=A3*B3"
The GCF is 12a2b4
Just choose the smaller exponent. The GCF of a3 and a5 is a3
(a - 1)(a^2 + a + 1)
gcd(a,b) = greatest common divisor (or factor, whatever) of a and b. For any set of number, a1, a2, a3, ..., you can use the Euclidean algorithm (http://en.wikipedia.org/wiki/Euclidean_algorithm) to get the gcd(a1, a2), and then again to get gcd(gcd(a1, a2), a3), etc. Often, though, you can eyeball it. So 24*3 = 72. Therefore, gcd(24, 72)=24. 24 does not divide 132, but 12 does (the next biggest factor of 24), so gcd(24, 72, 132)=12.
(a + 4)(a^2 - 4a + 16)
a(a^2 - 9a + 3)
(a - 2)(a^2 + 4)
a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
20 pence each
Sum and difference of two cubes is factored this way : a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
There following two options should work:=sum(A1:A3) or=A1+A2+A3
First you can factor a^2 from the first two terms and 4 from the last two terms. (a^2)(a-2)+4(a-2) You can see that they both have (a-2) as a factor. So it is (a^2+4)(a-2)