-119
Chat with our AI personalities
If you mean: n2+16n+64 then it is (n+8)(n+8) when factored
t(n) = n2 - 2n + 4
Let the smaller number be n then the other number is (n + 2). Then, n(n + 2) = 783 n2 + 2n = 783......which can be rearranged as : n2 + 2n - 783 = 0 This can be factored : n2 + 2n - 783 = (n + 29)(n - 27) = 0 The solution that concerns us is when n is positive. This occurs when, n - 27 = 0 : n = 27. Then the two consecutive odd numbers are 27 and 29.
n x n = n2
n2-3n+2