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Michael Kreiger
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∙ 14y ago(n + 11)(n - 11)
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What is factor of n2 16n 64?
If you mean: n2+16n+64 then it is (n+8)(n+8) when factored
What is algebraic expression for this pattern 3 4 7 12 19?
t(n) = n2 - 2n + 4
What are two consecutive odd numbers whose product is 783?
Let the smaller number be n then the other number is (n + 2). Then, n(n + 2) = 783 n2 + 2n = 783......which can be rearranged as : n2 + 2n - 783 = 0 This can be factored : n2 + 2n - 783 = (n + 29)(n - 27) = 0 The solution that concerns us is when n is positive. This occurs when, n - 27 = 0 : n = 27. Then the two consecutive odd numbers are 27 and 29.
How do you add n squared plus n squared?
n2 + n2 = 2 n2
What is n2 in math?
n x n = n2
N2 minus 11n minus 26 need to writte the expression in factored form?
n2 - 11n - 26what two factors of - 26 add up to - 11?(n + 2)(n - 13)===========
N2 plus 11n plus 18 need to writte the expression in factored form?
n2 + 11n + 18 = n2 + 2n + 9n + 18 = n(n+2) + 9(n+2) = (n+9)*(n+2)
What is factor of n2 16n 64?
If you mean: n2+16n+64 then it is (n+8)(n+8) when factored
How do you factor n2 plus 7n - 44?
To factor a trinomial (three-term expression) of the form n2+bn+c, find the two numbers h and k that are factors of c and add up to b. Then, write those numbers in this template: (n+h)(n+k) For the trinomial n2+7n-44, c = -44 and b = 7. The two numbers that are factors of -44 and add up to 7 are 11 and -4. So, the factored form would be (n+11)(n-4).
Are there infinitely many primes of the form n2-1 and n2-2 and n2-3 and n2-4?
n2-1 and n2-4 are trivial cases because of n2-m2=(n-m)(n+m). So the only prime of the form n2-1 is 3 and of the form n2-4 is 5.
What is the answer to n2 11n 18?
If you mean n squared+11n+18 then it is (n+2)(n+9) when factored
Sn is a function that squares numbers Find S11 when Sn equals n2?
121
What does n2 - 13n 42 equal?
If you mean: n^2 -13n +42 then it equals (n -6)(n -7) when factored
What would happen if NO were added to N2(g) O2(g) 2NO(g) at equilibrium?
More N2 and O2 would form
How do you solve this problem n2-3n-18?
This can not be solved as it is not an equation but a simple expression. If you are looking to factor it, then the answer is: n2 - 3n - 18 = (n - 6)(n + 3)
What is the equilibrium constant for the reaction N2(g) O2(g) 2NO(g)?
More NO would form
How do you factor 2nSquared-44n plus 242?
Factor 2n2 - 44n + 242 = f(n) the quick way: f(n) = 2 (n2 - 22n + 121) notice by sight that 22 is 2 * 11 and 121 is 11 squared. Set b = 11 f(n) = 2 (n2 - 2bn + b2 ) Now, factor the expression in brackets. The + and - signs show that both factors will have minus signs, so expect the form (a - b)(c -d). Check that both n and b occur in the middle term, so (n-b)(n-b) and therefore, f(n) = 2 (n - 11)2 Which is the answer.
