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Q: What is the cube root of the number 8?

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Take the cube root of that number. For example, volume is 8 square inches and the cube root of 8 is 2. In case you forgot, if N is the Cube root of a number M then NxNXN=M

To cube a number, you would multiply the number three times. The cube root is the root of the number before it is multiplied. For example, 2 times 2 times 2 is 8, so the cube root is 2.

the cube root of 125 is 5, the cube root of 64 is 4, the cube root of 27 is 3, the cube root of 8 is 2, and the cube root of 1 is 1.

The cube root of 8 is 2.

The cube root of -512 is: -8

The cube root of 512 is 8

square root is 8 (8 x 8 = 64)cube root is 4 (4 x 4 x 4 = 64)

The cube root of a number is a bit like the square root, except 3 instead of 2. What number times itself three times equals that number? For example, 2 is the cube root of 8 because 2x2x2=8 Consider a number n multiplied by itself three times. n x n x n = n^3 n is the cube root of n^3.

it is the number which when multiplied by itself three times give you the original number. For example, the cube root of 8 is 2 (2x2x2 = 8) This works for negative numbers as well Forexample, the cube root of -27 is -3 [(-3)x(-3)x(-3) = -27]

Cube root of -512 = -8

If the negative number is "-a", then you can say the cube root is "-(cube root of a)" Because if you cube a negative number, you get a negative number. So if you cube root a negative number, you get a negative number. Ex) cube root of -8 = -2 Because (-2)^3 = -8 But if you want to find the complex cube roots, you can make an equation: "x^3=-a" or "x^3+a=0" We know one of the roots is "-(cube root of a)" so you can factor the equation by (x+(cube root of a)) And then you use the quadratic formula for the quadratic equation you're left with. Ex) x^3=-8 or x^3+8=0 Since -2 is a root, factor it by (x+2) x^3+8=(x+2)(x^2-2x+4) Using the quadratic formula, you get "1+i√3" and "1-i√3" Therefore the three cube roots of -8 is <"-2", "1+i√3", "1-i√3">

The cubic root of -8 is -2.

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