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Derivative of 1/x

1/x = x-1

Take the derivative

(-1)x(-1-1) = -x-2 = 1/x2

Q: What is the derivative of 1 over x?

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The derivative is 1/(1 + cosx)

f(x)=xln(x) this function is treated as u*v u=x v=ln(x) The derivative of a product is f'(x)=u*v'+v*u' plugging the values back in you get: f'(x)=(x*dlnx/x)+(ln*dx/dx) The derivative of lnx=1/x x=u dlnu/dx=(1/u)*(du/dx) dx/dx=1 x=u dun/dx=nun-1 dx1/dx=1*x1-1 = x0=1 f'(x)=x*(1/x)+lnx*1 f'(x)=1+lnx Now for the second derivative f''(x)=d1/dx+dlnx/dx the derivative of a constant, such as 1, is 0 and knowing that the derivative of lnx=1/x you get f''(x)=(1/x)

(1/2(x^-1/2))/x

Write it as (1/3)x and take the derivative. You get (1/3)x0 = 1/3 * 1 = 1/3 ■

The partial derivative in relation to x: dz/dx=-y The partial derivative in relation to y: dz/dy= x If its a equation where a constant 'c' is set equal to the equation c = x - y, the derivative is 0 = 1 - dy/dx, so dy/dx = 1

Related questions

1/x = x-1d/dx(x-1) = -x-2 = -1/x2

The derivative of ln x is 1/x The derivative of 2ln x is 2(1/x) = 2/x

the derivative of 1x would be 1 the derivative of x to the power of 1 would be 1. the derivative of x+1 would be 1 the derivative of x-1 would be 1 im not sure what you are asking, but however you put it, it's 1.

the derivative of ln x = x'/x; the derivative of 1 is 0 so the answer is 500(1/x)+0 = 500/x

The derivative is 1/(1 + cosx)

4/x can be written as 4x-1 (the power of negative 1 means it is the denominator of the fraction) 4*-1 = -4 Therefore, the derivative is -4x-2

Given y=ln(1/x) y'=(1/(1/x))(-x-2)=(1/(1/x))(1/x2)=x/x2=1/x Use the chain rule. The derivative of ln(x) is 1/x. Instead of just "x" inside the natural log function, it's "1/x". Since the inside of the function is not x, the derivative must be multiplied by the derivative of the inside of the function. So it's 1/(1/x) [the derivative of the outside function, natural log] times -x-2=1/x2 [the derivative of the inside of the function, 1/x] This all simplifies to 1/x So the derivative of ln(1/x) is 1/x

X/1 is just X. so (1/2)X2 + C or X2/2 + C

x^0 = 1 for all x. The derivative of 1 is always zero.

Derivative of natural log x = 1/x

1/x

The derivative of tan(x) is sec2(x).(Which is the same as 1/cos2(x).