20x5 =100 20+5=25 100+25= 125
It is: (20*10)-(20+10) =170
To find the sum of the first 20 terms of an arithmetic progression (AP), we need to first determine the common difference (d) between the terms. Given that the 6th term is 35 and the 13th term is 70, we can calculate d by subtracting the 6th term from the 13th term and dividing by the number of terms between them: (70 - 35) / (13 - 6) = 5. The formula to find the sum of the first n terms of an AP is Sn = n/2 [2a + (n-1)d], where a is the first term. Plugging in the values for a (the 1st term), d (common difference), and n (20 terms), we can calculate the sum of the first 20 terms.
95
The factor pairs of 200 are (200,1)(100,2)(50,4)(40,5)(25,8)(20,10) None of them have a sum or difference of 20. Factors of 200 that add to 20 are 10 and 10.
Sum means add them together.15+20=35
It is: (20*10)-(20+10) =170
600 - 150 = 450
(12 * 8) - (12 + 8) = 96 - 20 = 76
4 and 5 have the sum of 9 and the product of 20.
The integers 2 and 10 have a product of 20 and a sum of 12.
The sum of two numbers between 20-40 is 58. The difference is 12
30
2 x 3 x 5 x 7 = 210 11 + 13 + 17 + 19 = 60 The difference is 150 .
The product of 20 and 35 is 700.
23 and 32
20 + 10 = 30 20 x 10 = 200 200 - 30 = 170 Your answer is 170.
5 and 4. 5x4=20 (product) 5+4=9 (sum)