Domian is x>-6
Range is y> or equal to 0
what is the domain of g(x) equals square root of x plus 1? √(x+1) ≥ 0 x+1≥0 x≥-1 Domain: [-1,∞)
To find the domain or range, solve for a variable and see if the other variable has any restrictions on it. In this case, x2 + y = 4 y = 4 - x2 There are no restrictions on x, therefore x is in the domain of all real numbers. x = square root(4 - y) Since the argument (number in brackets) of a square root must be positive, 4 - y > 0, y < 4. Domain: x can be all real numbers. Range: y can be all real numbers less than or equal to 4.
84
You never square a whole equation. That's just silly.
The range is {-7, 1, 9, 17}.
The range depends on the domain.
The domain and range are both [-6, +6].
It depends on the domain but, if the domain is the real numbers, so is the range.
Domain : set of all reals Range: set of all reals
The domain and range of Y = 1.3x + 8 are both [-infinity, +infinity]
The range depends on the domain and conversely.
The domain and range of the equation y = 2x+8 are both [-infinity,+infinity].
what is the domain of g(x) equals square root of x plus 1? √(x+1) ≥ 0 x+1≥0 x≥-1 Domain: [-1,∞)
If the domain is the real numbers then so is the range.
Y = x squared -4x plus 3 is an equation of a function. It is neither called a domain nor a range.
The answer depends on the domain for x. For example, if the domain is x = 7, then the range is 55. If the domain is all Real numbers, then the range is y >= 6.
If the domain is the set of real numbers, so is the range.