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x-intercept is -3, (-3, 0)

y-intercept is -2, (0, -2)

The line passes through these two points, (-3, 0) and (0, -2). Then the slope will be: m = (-2 - 0)/[0 - (-3)] = -2/3

Let's use one of the point; (-3, 0)

y - y1 = m(x - x1)

y - 0 = (-2/3)[x - (-3)]

y = (-2/3)x -2 This is the equation of the line. (This is the slope intercept form)

Or use the intercept form: x/a + y/b + 1, where a is x-intercept, and b is y-intercept. So,

x/-3 + y/-2 = 1

(x/-3)(-6) + (y/2)(-6) = -6

2x + 3y = -6, which is the general form of the equation for the line.

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16y ago

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