x-intercept is -3, (-3, 0)
y-intercept is -2, (0, -2)
The line passes through these two points, (-3, 0) and (0, -2). Then the slope will be: m = (-2 - 0)/[0 - (-3)] = -2/3
Let's use one of the point; (-3, 0)
y - y1 = m(x - x1)
y - 0 = (-2/3)[x - (-3)]
y = (-2/3)x -2 This is the equation of the line. (This is the slope intercept form)
Or use the intercept form: x/a + y/b + 1, where a is x-intercept, and b is y-intercept. So,
x/-3 + y/-2 = 1
(x/-3)(-6) + (y/2)(-6) = -6
2x + 3y = -6, which is the general form of the equation for the line.
Without the inclusion of an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation
3
That would be a linear equation.
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x - 4y = 3 is the slope of a line perpendicular to line whose equation is y -5 3x plus 8 3.
Without the inclusion of an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
A linear equation.
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That would be a linear equation.
yes
2y= 3x+6
It is the locus of all points whose coordinates satisfy the equation of the line.
A linear equation.
When a straight line equation is parallel to another equation the slope remains the same but the y intercept changes
y=mx+c
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