Without the inclusion of an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation
Get in slope intercept form. 3X + 5Y = 15 5Y = -3X + 15 Y = -3/5X + 3 -3/5 is the slope of this line and the line parallel to this line
Points: (3, 15) and (5, 9) Slope: -3
15
-5
-15-16/-7-19=-1/26
10y=15y=1.5
25
Get in slope intercept form. 3X + 5Y = 15 5Y = -3X + 15 Y = -3/5X + 3 -3/5 is the slope of this line and the line parallel to this line
Equation of given line: 3x + y = 15 or y = -3x + 15 Slope of given line = coefficient of x = -3 Slope of perperndicular = -1/(slope of given line) = -1 / (-3) = 1/3
Points: (10, 8) and (15, 8) Slope: 0 It will be a straight horizontal line
Points: (15, 8) and (7, 3) Slope: 5/8
10y + 8y = 18y = 15 y = 15/18 y = 5/6 = 0.833333.....
I'm assuming here that this line is a straight line. If so, it has the general equation y=mx+c (where m= the gradient/slope and c is the intercept). Substituting in the values provided in the question, we yield; 15= (9x9)+c We then solve and rearrange; 15=81+c 15-81=c -66=c. Therefore, the slope intercept is -66
When given two points use the equation :- m = [y(1) - y(2)] / [ x(1) - x(2)] NB The numbers above are 'markers' , NOT the coordinates of the given points. For the points (1,1) & ( 3,15) Substitute om m = [ 15 -1] /[ 3 - 1 ] => m = [ 14] / [2] => m = 14/2 Cancel down by '2' m = 7 the slope!!!!!
Points: (-1, -1) and (3, 15) Slope: 4
The slope of the line that represents the graph of that equation is 15.
4