If it a straight line with no y intercept, it must be parallel to the y-axis. So the equation is x = 3
that is an equation of a line with a slope of 1 and y-intercept of -3 and x-intercept of 3
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The equation is y = 5x - 15 or y = 5*(x - 3)
x-intercept is -3, (-3, 0) y-intercept is -2, (0, -2) The line passes through these two points, (-3, 0) and (0, -2). Then the slope will be: m = (-2 - 0)/[0 - (-3)] = -2/3 Let's use one of the point; (-3, 0) y - y1 = m(x - x1) y - 0 = (-2/3)[x - (-3)] y = (-2/3)x -2 This is the equation of the line. (This is the slope intercept form) Or use the intercept form: x/a + y/b + 1, where a is x-intercept, and b is y-intercept. So, x/-3 + y/-2 = 1 (x/-3)(-6) + (y/2)(-6) = -6 2x + 3y = -6, which is the general form of the equation for the line.
Points: (2, 0) and (0, -6) Slope: 3 Equation: y = 3x -6
X = 3whew !
that is an equation of a line with a slope of 1 and y-intercept of -3 and x-intercept of 3
If the x intercept is a and the y intercept is b, then the equation of the line is bx + ay = ab
y = mx - 3 where m is a constant.
y=-4thirds x plus 4.
-8
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It is: y = x+3 whereas 1 is the slope and 3 is the y intercept
The is a straight line parallel to the y-axis with an x intercept at -3.
It is: y = x+3
For the x intercept, put y = 0 in the equation. So 5x = 15 ie x = 3 So the intercept is (3,0)
The equation is y = 5x - 15 or y = 5*(x - 3)