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Q: What is the exact trigonometric function value of cot 0?

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cot 15 = cot(45 - 30) = cot45.cot30 - 1 / cot45 + cot 30

cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)

The six main trigonometric functions are sin(x)=opposite/hypotenuse cos(x)=adjacent/hypotenuse tan(x)=opposite/adjacent csc(x)=hypotenuse/opposite cot(x)=adjacent/opposite sec(x)=hypotenuse/adjacent Where hypotenuse, opposite, and adjacent correspond to the three sides of a right triangle and x corresponds to an angle in that right triangle.

cot 32° = 1/(tan 32°) = 1/(0.6249) = 1.6003

(c2) / (2 cot A + cot B) = Area of Triangle ABC

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cot(A+B+C) is, itself, a trigonometric function, so the question does not really make any sense!

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cot 15 = cot(45 - 30) = cot45.cot30 - 1 / cot45 + cot 30

cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)

cot(115º) = -tan(25) or cot(115º) = -0.466308

There r 6 trignometric functions,namely sin a cos a tan a cosec a sec a cot a where a is the angle. Trigonometric functions didn't exist without angles.

sin(90Â°) = 1 cos(90Â°) = 0 tan(90Â°) = âˆž sec(90Â°) = âˆž csc(90Â°) = 1 cot(90Â°) = 0

tan6=cot(90-6) = cot 84

To simplify such expressions, it helps to express all trigonometric functions in terms of sines and cosines. That is, convert tan, cot, sec or csc to their equivalent in terms of sin and cos.

The most easiest method to solve trigonometric problems is to be place the values of the sin/cos/tan/cot/sec/cosec . The values will help to solve the trigonometric problems with less difficulty.

Using the Circle Unit which is a chart used in precal and calc classes, you can see that angle 150 in radians is 5pi/6. Using this, the cot value is -Root3.

May of the prints are valued in price close to $25 each. The exact will vary depending upon the condition of the print.

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