The two are related. The answer could be base 2, exponent 18 or base 8, exponent 6 or base 10, exponent 5.4185 or base 262144, exponent 1 or base 68,719,476,736 and exponent 0.5
Yes, you can, but it starts getting complicated. You can, for example have a number raised to an exponent that is itself a number raised to an exponent, or you can have a number raised to an exponent and the result raised to another exponent.
yes it can if the exponent is 1.
In exponent form, we have 52 x 62.
1, if the exponent is not shown.
Express 2 times 128 times 32 times 16 as an exponent of two
128 is neither a perfect square nor a perfect cube, it is 2⁷ (2 to the 7th power).
27 = 128 = (1 x 100) + (2 x 10) + (8 x 1)
The exponent.
if there is no exponent shown, then the exponent is 1. ex: 41
Yes, 25 CAN BE and exponent. Any number can be and exponent
The exponent is a characteristic of a number. A measurement unit does not have an exponent. Since a metre is a measurement unit, it does not have an exponent.
Power = 5 = exponent. That is, exponent = 5.
what is the loose exponent
you get an exponent when you multiply EXAMPLE 10x10x10=1000 that is an exponent NO DONT THINK THAT IF THE EXPONENT IS 3 YOU MULTIPLY IT BY 3 NO WAY JOSE
The two are related. The answer could be base 2, exponent 18 or base 8, exponent 6 or base 10, exponent 5.4185 or base 262144, exponent 1 or base 68,719,476,736 and exponent 0.5
128 = x7 (we see that x > 0, since x is raised to an odd power) 27 = x7 (this is true only when x = 2) 2 = x Remember that a logarithm is an exponent. The statement 128 = x7 is equivalent to logx 128 = 7. logx 128 = 7 log 128/log x = 7 (or reverse the both sides) log x/log 128 = 1/7 (multiply by log 128 to both sides) log x = log128/7 (or use base 10 for the logarithm) log10 x = log128/7 (write the equivalent statement) 10log 128/7 = x 2 = x or use the natural log, ln. 128 = x7 ln 128 = ln x7 ln 128 = 7ln x (ln 128)/7 = ln x e(ln128)/7 = elnx (elnx = x ) 2 = x