NO!!! '27' is a multiple of '9' However, '9' is a factor of '27'
The factor pairs of 27 are 1x27 and 3x9.
To find the factor tree for 1350, you start by finding two factors of 1350, such as 27 and 50. Then, you continue breaking down these factors into their prime factors until all branches of the tree end in prime numbers. The factor tree for 1350 would show its prime factorization as 2 x 3 x 3 x 3 x 5 x 5.
27=3*3*3. Those are the prime factors of 27. You could say that 9 is a factor of 27 since 27=3*9. Bfut the largest is 27 since 27=1*27.
The GCF is 27.
27 9,3 3,3,3
27 9,3 3,3,3
27 3,9 3,3,3
27 9,3 3,3,3
27 3, 9 3, 3, 3
27 9,3 3,3,3
No you cannot. You might want to try the factor tree for 27.
27 9,3 3,3,3
27 9,3 3,3,3 52 26,2 13,2,2
Is this about drawing factor tree of 27? If this is so: ...........27 .........../ \ .........9 * 3 ......../ \ ......3 * 3 Prime Factorization of 27 = 3 * 3 * 3
27 9,3 3,3,3 36 18,2 9,2,2 3,3,2,2
54/\27 2/\9 3/\3 32x3x3x3 or 2x33