The factors of 81 are: 1, 3, 9, 27, 81.
15,3 3,5,3
27 9,3 3,3,3 36 18,2 9,2,2 3,3,2,2 The GCF is 3 x 3, or 9.
9x9=81. Proving that one of the factor trees for 81 is 9xp.
I can't make the actual lines, but there's a factor tree. 104 2 * 52 2 * 26 2 * 13 2*2*2*13=104
No you cannot. You might want to try the factor tree for 27.
27 9,3 3,3,3
27 9,3 3,3,3
27 9,3 3,3,3
27 3, 9 3, 3, 3
27 9,3 3,3,3
In the case of 27, there is only one possible factor tree - using the factors 3 and 9 as the first step. 27 3 x 9 3 x (3x3)
27 9,3 3,3,3
The factor tree is as follows: 114 57,2 19,3,2
no
No.
27 9,3 3,3,3 52 26,2 13,2,2