You cannot really make a factor tree for 7 because it is already a prime number.
The factors of 81 are: 1, 3, 9, 27, 81.
15,3 3,5,3
27 9,3 3,3,3 36 18,2 9,2,2 3,3,2,2 The GCF is 3 x 3, or 9.
9x9=81. Proving that one of the factor trees for 81 is 9xp.
No you cannot. You might want to try the factor tree for 27.
27 9,3 3,3,3
27 9,3 3,3,3
27 9,3 3,3,3
27 3, 9 3, 3, 3
27 9,3 3,3,3
In the case of 27, there is only one possible factor tree - using the factors 3 and 9 as the first step. 27 3 x 9 3 x (3x3)
27 9,3 3,3,3
The factor tree is as follows: 114 57,2 19,3,2
no
You cannot really make a factor tree for 7 because it is already a prime number.
No.