3X3 + 6X2 - 24X
3X(X2 + 2X - 8)
3X(X + 4)(X - 2)
================assuming that last term was - 24X
3x(x2 + 2x - 4)
3x3 + 6x2 - 24x = 3x(x2 + 2x - 8) = 3x(x2 + 4x - 2x - 8) = 3x[ x(x + 4) - 2(x + 4) ] = 3x(x - 2)(x + 4)
-3x3 - 6x2 + 189x = -3x(x2 + 2x - 63) = -3x(x + 9)(x - 7)
One-houndred and thirty five.
(3x^2+5)(x+2). APEX CHEATERS UNIT.....
Divide all terms by 3 and it is: (2x-1)(x+2)
3/(x2+4x-1) = 6/(2x2-3x+5) Cross - multiply in order to eliminate the fractions: 6*(x2+4x-1) = 3*(2x2-3x+5) 6x2+24x-6 = 6x2-9x+15 6x2-6x2+24x+9x = 15+6 33x = 21 x = 21/33 => x = 7/11
6(x2 -4x - 12) 6(x-6)(x+2)
9+6x2=21
2x(x2 + 3x - 7)
Since you add up the 'x''s (i.e. (2x) (3x) (4x) = 24x cubed) 6x2
6x2 + 10x = 2x(3x + 5)