Pi to 33 decimal places = 3.141592653589793238462643383279502 So, the number 0 is the 33rd digit (of you count the 3 before the decimal place) But, if you count after the decimal place, then it is the number 2.
Count the number of distinct elements in the set.
The class that has the highest frequency (number)
899
It is called the range.
There is no such number. If we could count to any particular number, then we can always count to the next one. And then the next. And so on.
A circle has no beginning.
its as far as you can count
Lets assume you know how to count that well by age 5. If you spend every waking moment counting sequentially, one integer at a time, and retain your mental faculties until age 80, you might be able to reach 1,500,000,000.
The answer is 15.
5
1 is the highest number you can count to using a mod-2 counter.
the highest number you can count up to using 10 bits is 1029 using binary
import java.util.Scanner; //A class to find the highest number of 10 user inputs public class HighApp{ public static void main(String[]args){ Scanner scan = new Scanner(System.in); int count = 0; System.out.println("Enter number " + count); int highest = scan.nextInt(); //first, assume highest count ++; while(count <= 10){ System.out.println("Enter number" + count); int input = scan.nextInt(); if (input > hightest){ highest = input }//end if statement count++; }//end while loop System.out.println("The highest number entered was " + highest); }//end main method }//end HighApp class
Not in your lifetime.
It's the highest one can count with numerals without repeating them.
Thompson sheets offer the highest thread count at 800.