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What is the least number of bits to express 12?
Four bits are required to write '12' as a binary number.(12)10 = ( 1 1 0 0 )2
What is the largest 10 bit number?
Assuming you interpret the bits as an unsigned number, that would be 1111111111 in binary, or 1023 (210 - 1) in decimal.
What is whole numbers less than 6?
1,2,3,4,5. Count everything less than the number you mainly useing. Like in this case your Number is 6. Lets try one. Okay 10, Count 1,2,3,4,5,6,7,8,9. But NOT ten.
What is the number 2.4 in the form of a fraction using integers to show it's a rational number?
24/10
How does decimal value waste memory space?
A decimal digit requires 4 bits of memory space to represent all possible values. So N decimal digits will require 4N bits to store in decimal format. On the other hand, if the same N decimal digits were stored as a binary number, they should require log2(10N) bits, that is, about 3.32N bits. So storing the decimal representation uses about 20% more memory. To put it another way, 4 bits is capable of holding one of 16 different values. By using it to store decimal digits, it is only being used to hold one of 10 different values.
What is the maximum number that you can count up to using 10 bits14 bits and count up to a maximum of 511 63?
Using n bits, you can count to 2n - 1. This is for unsigned integers. So 10 bits = 210 - 1 = 1023 14 bits = 214 - 1 = 16383 To count to 511 you need log2(511+1) = log2(512) = 9 bits. To count to 63 you need log2(63+1) = log2(64) = 6 bits.
How many binary bits are required to represent the decimal number 643?
Count them: 643(10)=1010000011(2)
The minimum number of bits required to store the hexadecimal number FF is?
To store the hexadecimal number FF, we need to convert it to binary first. FF in hexadecimal is equivalent to 1111 1111 in binary, which requires 8 bits to represent. Each hexadecimal digit corresponds to 4 bits in binary, so two hexadecimal digits (FF) require 8 bits to store.
What numbers can be stored using 32-bit binary?
A 32 binary number is a number stored by a computer in 32 bits. it can represent: 1) An unsigned number in the range 0 to 4,294,967,295 2) A signed number in the range -2,147,483,648 to 2,147,483,647 3) A single precision IEEE floating point number with 1 sign bit, 8 exponent bits and 23 mantissa bits give an accuracy of about 7.2 decimal digits and a range of ± 10^-38 to 10^38
How many bits are required in decimal numbers in range 0 to 999 using Straight binary code and BCD code?
10 bits would be required. 10 bits long (10 digits long) can represent up to 1024.
Can you give me 10 sentences with count nouns?
You can create 10 sentences with count nouns by using the words many bottles, few bottles, and a few bottles in different sentences. When using count nouns they can be preceded by much.
What is the least number of bits to express 12?
Four bits are required to write '12' as a binary number.(12)10 = ( 1 1 0 0 )2
What does the decimal number 255 mean in binary?
Oh, dude, you're asking about binary now? Alright, so in binary, the decimal number 255 is represented as 11111111. It's like all those ones are just hanging out together, having a binary party. So yeah, 255 in binary is just a bunch of ones chilling together.
What are the advantages of using base 10 for people?
Some advantages of uisng base 10 for people are that for a number like 57, you can just say 57 instead of 111001. Also, humans have 10 finger to count on.=P
What is the Octal number system?
The Octal number system is a numeral system based on the number 8 (as opposed to 10). Interestingly, the cultures that have adopted this system count using the spaces between their fingers instead of the individual fingers themselves.
How long would a 10mb animation take to transfervia 100 gbps channel?
Here is how you calculate that. 10MB is 10 million bytes (more precisely, 10 x 1024 x 1024). Multiply that by 8 to convert to bits (since bandwidth is measured in bits per second). gbps means billions of bits per second. Now divide the total number of bits by the bandwidth (in bits/second). The result is the number of seconds it takes.
How many bits can the noise affect?
10 bits
