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For it to be a definite integral, you would need to specify a range. We can however give you the indefinite integral. The easiest way to do this is to think of it not as a fraction, but as a negative exponent: 1/x2 = x-2 It then becomes quite easy to integrate, as we can say in general: ∫(axn) dx = ax(n + 1) / (n + 1) + C In this case then, we have: ∫(x-2) dx = -x-1 + C, or -1/x + C
it's the bit in the square root sqrt of (b squared minus 4ac) when a,b and c are the values belonging to the equation ax(sqared) plus bx plus c
AX + BY is not an equation .AX + BY + C = 0is the general equation for a straight line.
A linear equation.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals", "squared". There is no equation (nor inequality) in the question, not even a valid expression. So there is nothing that can be solved.