What is the definite integral of 1 divided by x squared?

Answer 1

For it to be a definite integral, you would need to specify a range. We can however give you the indefinite integral. The easiest way to do this is to think of it not as a fraction, but as a negative exponent:

1/x2 = x-2

It then becomes quite easy to integrate, as we can say in general:

∫(axn) dx = ax(n + 1) / (n + 1) + C

In this case then, we have:

∫(x-2) dx = -x-1 + C, or -1/x + C

Answer 2

There can be no definite integral because the limits of integration are not specified.

The indefinite integral of 1/x2 is -1/x + C