0
For it to be a definite integral, you would need to specify a range. We can however give you the indefinite integral. The easiest way to do this is to think of it not as a fraction, but as a negative exponent:
1/x2 = x-2
It then becomes quite easy to integrate, as we can say in general:
∫(axn) dx = ax(n + 1) / (n + 1) + C
In this case then, we have:
∫(x-2) dx = -x-1 + C, or -1/x + C
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What is the integral of 1 divided by x squared?
The indefinite integral of (1/x^2)*dx is -1/x+C.
What is the integral of cot squared x?
ln(sinx) + 1/3ln(sin3x) + C
What is the integral of 1 divided by xln2x?
0.5
What is the integral of x divided by x plus 1?
x/(x+1) = 1 - 1/(x + 1), so the antiderivative (or indefinite integral) is x + ln |x + 1| + C,
What are four squared divided by two to the fourth power?
1
What is the connection between anti-derivatives and definite integrals?
Definite integrals are definite because the limits of integration are prescribed. It is also the area enclosed by the curve and the ordinates corresponding to the two limits of integration. Antiderivatives are inverse functios of derivatives. If the limits of the integral are dropped then the integration gives antiderivative. Example Definite integral of x with respect to x between the value of x squared divided by 2 between the limits 0 and 1 is 1/2. Antiderivative of x is x squared divided by two.
What is the integral of 1 divided by x squared?
The indefinite integral of (1/x^2)*dx is -1/x+C.
What is the integral of 1 divided by 2x squared?
0.5
How do you integrate the integral of quantity of x plus 2 divided by x squared plus x plus 1?
3
What is the integral of 1 divided by the cosine squared of x with respect to x?
∫ 1/cos2(x) dx = tan(x) + C C is the constant of integration.
What is the integral of 1 divided by the sine squared of x with respect to x?
∫ 1/sin2(x) dx = -cot(x) + CC is the constant of integration.
What is the integral of 1 over x squared plus 1?
arctan(x)
When you find particular integral then why you not add constantof integration?
Where you refer to a particular integral I will assume you mean a definite integral. To illustrate why there is no constant of integration in the result of a definite integral let me take a simple example. Consider the definite integral of 1 from 0 to 1. The antiderivative of this function is x + C, where C is the so-called constant of integration. Now to evaluate the definite integral we calculate the difference between the value of the antiderivative at the upper limit of integration and the value of it at the lower limit of integration: (1 + C) - (0 + C) = 1 The C's cancel out. Furthermore, they will cancel out no matter what the either antiderivatives happen to be or what the limits of integration happen to be.
What is the integral of the square root of x minus 1 squared?
the integral of the square-root of (x-1)2 = x2/2 - x + C
How do you evaluate definite integrals?
In order to evaluate a definite integral first find the indefinite integral. Then subtract the integral evaluated at the bottom number (usually the left endpoint) from the integral evaluated at the top number (usually the right endpoint). For example, if I wanted the integral of x from 1 to 2 (written with 1 on the bottom and 2 on the top) I would first evaluate the integral: the integral of x is (x^2)/2 Then I would subtract the integral evaluated at 1 from the integral evaluated at 2: (2^2)/2-(1^2)/2 = 2-1/2 =3/2.
how do you symplify 3a squared divided by 3a squared?
1
What equals 1 cos squared x divided by cos squared x?
1. Anything divided by itself always equals 1.
