Integral of sqrt(2x) = integral of (2x)1/2 = √2/(3/2)*(x)3/2 + c = (2√2)/3*(x)3/2 + c
where c is the constant of integration.
Check: ( (2√2)/3*(2x)3/2 + c )' = (2√2)/3*(3/2)(x)(3/2)-1 + 0 = √2*(x)1/2 = √2x
the square root of 164= 2x the square root of 41
The square root of 4x^2 is solved by first doing the square root of 4. This is plus or minus two - because -2 x -2=4. The square root of x^2 is x. So the answers are 2x or -2x. If your question was (4x)^2, then the answer would be 4x.
84
is (x^2)/2=x then (x^2)=2x then x=square root of (2x)
Let the width = X. The length is twice the width plus 5. So the length must be 2X + 5. Area = 63 ft squared = X multiplied by 2X + 5 = 2X squared + 25. 2X squared = 63 - 25 = 38 2X = square root of 38. Therefore the width is the square root of 38 divided by 2 and the length is the square root of 38 plus 5.
- ln ((x^2)-4)
the square root of 164= 2x the square root of 41
the integral of the square-root of (x-1)2 = x2/2 - x + C
the square root of 164= 2x the square root of 41
replace square root o x with t.
square root x
7
The square root of 28 is an irrational number that can't be expressed as a fraction
The square root is not integral : about 7585.998 (round to 7586 - this square is 54547396, so this could be a transposition error).
Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)
Its the square root of 2 times x Ambiguous. More clear is x times square root of 2
The answer is yes. Perhaps the question needs to be reworded.