the square root of 164= 2x the square root of 41
The square root of 4x^2 is solved by first doing the square root of 4. This is plus or minus two - because -2 x -2=4. The square root of x^2 is x. So the answers are 2x or -2x. If your question was (4x)^2, then the answer would be 4x.
84
is (x^2)/2=x then (x^2)=2x then x=square root of (2x)
The integral of root(sin(x)) is -2 time the elliptic integral of the second order of .25(pi-2x) at 2. For this and other integrals, go to http://integrals.wolfram.com/index.jsp?expr=sqrt(sin(x))&random=false For more information on the elliptic integral functions, go to http://en.wikipedia.org/wiki/Elliptic_integral Hope this helps!
- ln ((x^2)-4)
the square root of 164= 2x the square root of 41
the integral of the square-root of (x-1)2 = x2/2 - x + C
the square root of 164= 2x the square root of 41
replace square root o x with t.
square root x
7
The square root of 28 is an irrational number that can't be expressed as a fraction
The square root is not integral : about 7585.998 (round to 7586 - this square is 54547396, so this could be a transposition error).
Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)
Its the square root of 2 times x Ambiguous. More clear is x times square root of 2
Integral of 1 is x Integral of tan(2x) = Integral of [sin(2x)/cos(2x)] =-ln (cos(2x)) /2 Integral of tan^2 (2x) = Integral of sec^2(2x)-1 = tan(2x)/2 - x Combining all, Integral of 1 plus tan(2x) plus tan squared 2x is x-ln(cos(2x))/2 +tan(2x)/2 - x + C = -ln (cos(2x))/2 + tan(2x)/2 + C