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The length of a rectangle is five feet more than twice its width and the area of the rectangle is sixty-three Find the dimensions of the rectangle?
Let the width = X. The length is twice the width plus 5. So the length must be 2X + 5. Area = 63 ft squared = X multiplied by 2X + 5 = 2X squared + 25. 2X squared = 63 - 25 = 38 2X = square root of 38. Therefore the width is the square root of 38 divided by 2 and the length is the square root of 38 plus 5.
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We are interested in the dimensions of a certain rectangle. This rectangle has length twice the side of the square and width three units less than its sides of this square. If the two areas are equal?
The rectangle is 12 units by 3 units.
When The perimeter of a rectangle is 46. The lenght is one less than twice the width. Find the dimensions?
The dimensions work out as length 15 units and width 8 units Check: 2*(15+8) = 46 units which is its perimeter
The length of a rectangle is twice its width If the perimeter is 84cm what are the dimensions of the rectangle?
Let the length be 2x and the width be x: Perimeter = 2(2x+x) = 84 4x+2x = 84 6x = 84 Divide both sides of the equation by 6 to find the value of x: x = 14 Therefore: length = 28cm and width = 14cm
The perimeter of a rectangle is 50 meters and its length is 12 meters. What is the width of the rectangle?
The width of the rectangle is 13 meters. The perimeter of the rectangle is 50 meters, and its length is 12 meters. The 50 meters is 2 times the length plus 2 times the width. With a length of 12 meters, twice that is 24 meters. That leaves 50 meters - 24 meters for twice the width. And 50 - 24 = 26, which is twice the width. The 26 meters divided by 2 = 13 meters, which is the width of the rectangle.
What is the formula to find the length of a rectangle when the perimeter and width is already given?
Length = (Perimeter - twice width) / 2
There area of the rectangle is 128. If the width is twice the length what is the length?
The dimensions are 16 units by 8 units of mearsurement
When The width of a rectangle is 3 more than twice its length. The perimeter is 60 feet. Find the width and length of the rectangle.?
The dimensions of the rectangle are 21 units by 9 units
How does increasing the dimensions of a rectangle impact the perimeter?
If you increase the rectangle's length by a value, its perimeter increases by twice that value. If you increase the rectangle's width by a value, its perimeter increases by twice that value. (A rectangle is defined by its length and width, and opposite sides of a rectangle are the same length. The lines always meet at their endpoints at 90° angles.)
The length of a rectangle is 5 cm more than twice the width The perimeter of the rectanle is 34 cm find the dimensions of the rectangle?
4cm by 13cm
The area of a rectangle is 36 square inches the length is 1 inch more than twice the width what are the dimensions of the rectangle?
9" x 4"
How much fencing will be needed to fence a property that is 78 meters long and 65 meters wide?
For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.
What is the perimeter of a rectangle with length 42 inches?
A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.
Area 450 square meters. Length twice as long as width. What are the dimensions of this rectangle?
It is: 15 meters by 30 meters
The length of a rectangle is twice its width If the perimeter of the rectangle is 54y find its area?
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The width of a rectangle is 6 kilometers less than twice its length if its area is 80 square kilometers find the dimensions of the rectangle?
this is a funky question... 8x10 kilometers
The length of a rectangle is 3 ft more than twice its width and the area of the rectangle is 35 ft squared Find the dimensions of the rectangle?
if the width is 3.5 then the length is 10 10 = 3 +2(3.5) 10 x 3.5 = 35
The length of a rectangle is twice the width width the perimeter is 48 in find the dimensions of the rectangle?
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
