y = 5x + 1
y - 1 = 5x
(y - 1) / 5 = x
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If you mean: y = 5x-2 then the perpendicular slope is -1/5
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To find the inverse of a function, you have to switch y for x and then solve for y again. These are the steps: y = 5x - 20 x = 5y - 20 5y = x + 20 y = 0.2x + 4 or f(x)^-1 = 0.2x + 4
It is slope intercept form. The equation for slope intercept form is y=mx+b which is like your equation y=5x+6
If f(x)=(5x-1)/9 Then the inverse is x=(5y-1)/9 9x=5y-1 9x+1=5y (9x+1)/5=y The inverse is f(x)=(9x+1)/5
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To find the inverse of the equation ( y = 3x + 1 ), we first solve for ( x ) in terms of ( y ). Rearranging gives ( x = \frac{y - 1}{3} ). Therefore, the equation of the inverse is ( y = \frac{x - 1}{3} ).
To find the inverse of the equation ( y = 5x + 20 ), we first switch ( x ) and ( y ), giving us ( x = 5y + 20 ). Next, we solve for ( y ) by isolating it: ( 5y = x - 20 ) and then ( y = \frac{x - 20}{5} ). Thus, the inverse function is ( y = \frac{x - 20}{5} ).
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It is: y = -1/5x-2
It is: y = -1/5x+7 that is perpendicular to y = 5x+7
Follow this example. f(x) = (x+3)/5 To find its inverse, write y=f(x) y= (x+3)/5 Interchange x and y x = (y+3)/5 solve for y in terms of x 5x=y+3 y=5x-3 The inverse of f(x) is f^-1(x) = 5x-3
Write out equation - 10y - 5x= - 20 Negate equation 10y + 5x = 20 Isolate y variable 10y = - 5x + 20 Divide equation by 10 y= -1/2x + 2
To solve for the inverse of an equation, first, replace the function notation (e.g., (y = f(x))) with (y). Then, swap the roles of (x) and (y) in the equation. After that, solve for (y) in terms of (x). Finally, replace (y) with (f^{-1}(x)) to express the inverse function.
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