It is: y = -1/5x-2
(0,-3)
If the second equation is: y minus 2x equals 3, then:y - 2x = 3 ⇒ y = 2x + 3 and it is parallel to y = 2x.Otherwise (with with missing operator as "plus", "multiply" or "divide"), the lines are neither parallel nor perpendicular.
x = 4 and y = 7
The solution pair is (-7, 22), demonstrated as follows: (1) x + y = 15 : given; (2)4x + 3y = 38 : given; (3)3x + 3y = 45 : equation (1), multiplied by 3; (4) x = -7 : equation (2), minus equation (3); (5) y = 22 : equation (1), minus equation (4).
Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point: (7, 5) Equations intersect: (4, 1) Perpendicular distance: square root of [(7-4)2+(5-1)2] = 5
[ y = 2x plus or minus any number ] is parallel to it. [ y = -0.5x plus or minus any number ] is perpendicular to it.
(0,-3)
Get the slope of the given line, by putting it into slope-intercept form. Then you can divide minus one by this slope, to get the slope of any perpendicular line.
The required equation is: -7x = 63
If the second equation is: y minus 2x equals 3, then:y - 2x = 3 ⇒ y = 2x + 3 and it is parallel to y = 2x.Otherwise (with with missing operator as "plus", "multiply" or "divide"), the lines are neither parallel nor perpendicular.
x = 4 and y = 7
3x-4y-6 = 0
Here are the key steps:* Find the midpoint of the given line. * Find the slope of the given line. * Divide -1 (minus one) by this slope, to get the slope of the perpendicular line. * Write an equation for a line that goes through the given point, and that has the given slope.
It is: minus 1.25
The solution pair is (-7, 22), demonstrated as follows: (1) x + y = 15 : given; (2)4x + 3y = 38 : given; (3)3x + 3y = 45 : equation (1), multiplied by 3; (4) x = -7 : equation (2), minus equation (3); (5) y = 22 : equation (1), minus equation (4).
Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point: (7, 5) Equations intersect: (4, 1) Perpendicular distance: square root of [(7-4)2+(5-1)2] = 5
x = 4 and y = 7 which will satisfy both equations