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What is the ordered pair for 2y equals 4x-16 and 5y equals 4x plus 8?
2y = 4x - 16 5y = 4x + 8 Subtract the first equation from the second: 3y = 24 so that y = 8 Substitute this into the first equation: 16 = 4x - 16 ie 32 = 4x so that x = 8 So the solution is (8, 8)
-20x 5y equals 40 changed to slope-intercept form?
If the equation is -20x-5y=40 then the answer is -5y=20x+40 which equals y=-4x-8 If the equation is -20x+5y=40 then the answer is 5y=20x+40 which equals y=4x+8
4x plus 5y 40?
If you mean: 4x+5y = 40 then y = -0.8x+8 whereas as -0.8 is the slope and 8 is the y intercept of a straight line equation
8 plus y equals 7 plus 5y?
8+y = 7+5y y-5y = 7-8 -4y = -1 y = 1/4
5y plus 8 equals 7y-6?
5y+8 = 7y-6 5y-7y = -6-8 -2y = -14 y = 7
What is the ordered pair for 2y equals 4x-16 and 5y equals 4x plus 8?
2y = 4x - 16 5y = 4x + 8 Subtract the first equation from the second: 3y = 24 so that y = 8 Substitute this into the first equation: 16 = 4x - 16 ie 32 = 4x so that x = 8 So the solution is (8, 8)
-20x 5y equals 40 changed to slope-intercept form?
If the equation is -20x-5y=40 then the answer is -5y=20x+40 which equals y=-4x-8 If the equation is -20x+5y=40 then the answer is 5y=20x+40 which equals y=4x+8
Solve by the substitution method 4x-5y equals -8 4x plus 40 equals y?
4x-5y = -8 4x+40 = y => y = 4x+40 Substitute the value of y into the top equation: 4x-5(4x+40) = -8 4x-20x-200 = -8 4x-20x = 200-8 -16x = 192 Divide both sides by -16 to find the value of x: x = -12 Substitute the value of x into the original equations to find the value of y: Therefore: x = -12 and y = -8
4x plus 5y 40?
If you mean: 4x+5y = 40 then y = -0.8x+8 whereas as -0.8 is the slope and 8 is the y intercept of a straight line equation
8 plus y equals 7 plus 5y?
8+y = 7+5y y-5y = 7-8 -4y = -1 y = 1/4
What is the value of y if 5y plus 8 equals 7y?
5y+8=7y 2y=8 y=4
What is 18 equals 8 plus 5y?
8 + 5y = 18 Therefore, 5y = 10 y = 10/5 y = 2
4x-y equals 32 4x plus 5y equals -16?
Presumably this is a simultaneous equation question in the form of: 4x-y = 32 4x+5y = -16 Subtract the bottom equation from the top equation remembering that a -- is equal to a + so 32--16 is +40 and that -+5y-y is -6y: -6y = 48 Divide both sides by -6 to find the value of y: y = -8 Substitute the value of y into the original equations to find the value of x: So: x = 6 and y = -8
4x plus 32 equals -4x plus 16 x equals?
4x+32=-4x+16x4x+32=12x-4x -4x32=8x/8 /84=x
5y plus 8 equals 7y-6?
5y+8 = 7y-6 5y-7y = -6-8 -2y = -14 y = 7
Find the value of y if 5y plus 8 equals 7y?
5y+8=7y subtract 5y from each side , 5y+8=7y -5y -5y 8=2y /2 /2 4=y
What is the answer to 3y plus 5y equals 64?
y=8
