That depends on many factors. Best way is to measure the particular model of TV in question. Next best is to read the published dimensions in a catalog or other marketing material, though these are not always exactly correct. There may be protrusions for antenna, cables or space required around the set for mounting, cooling, operating controls or your hand while connecting. To get an approximation we need to answer these questions: * Widescreen or Standard aspect ratio? * ** Widescreen is in the ratio 16wide x 9high ** Standard is in the ratio 4wide x 3high * Does "54 tv" refer to a diagonal corner to corner measurement in inches? * How much area borders the screen? * ** What sides are the speakers on and how big are they? * What type of TV is it? determines depth or length. * ** Tube about 30" ** Projection about 24" ** Flat panel plasma or LCD about 4" So for a widescreen the screen dimension would be about * Your viewing area is 47.1 in(w) x 26.5 in(h) * Total viewing area is 1248.15 sq in. For a standard screen * Your viewing area is 43.2 in(w) x 32.4 in(h) * Total viewing area is 1399.68 sq in. Assuming a 54" widescreen LCD with speakers on the side, total outside dimensions would be approximately 57"w x 36"h x 4"l plus add 1.5"mounting depth if wall mounted.
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Let its width be x:- 2(2x+x) = 54 => 4x+2x = 54 => 6x = 54 => x = 9 Therefore: width = 9 cm and length = 18 cm
depends on brand and which TV of that brand
6w * w =54w=3L= 6*3=18
2*(length + width) = 54 feet.
A contractor needs 54 square feet of brick to construct a rectangular walkway. The length of the walkway is 15 more than the width Write an equation that is the answer? Ans: I L = length and W = width, then L = W + 15; area = LW = 54, so (W+15)W = 54, i.e. WxW + 15W - 54 = 0; solving this gives W = 3, so L = 18.