Length is 12ft, width is 4 ft.
2 x (length + width) = perimeter = 32 ft
⇒ length = 16ft - width [1]
length x width = area = 48 sq ft
Using [1] above:
⇒ (16ft - width) x width = 48 sq ft
multiplying out and rearranging:
⇒ width2 - 16 x width + 48 = 0
factorizing:
⇒ (width - 4)x(width - 12) = 0
Thus width = 4 or 12, so using [1] above:
⇒ width = 4ft, length = 16 - 4 = 12ft
or width = 12ft, length = 16 - 12 = 4ft
Convention is that the length is larger than the width, thus rectangle is 12ft long by 4 ft wide.
The perimeter of any rectangle is [ 2 x (length + width) ]. Since the length and width of a square are equal, the perimeter of a square is also [ 2 x (side + side) ] = (4 x side).
Length = (Perimeter - twice width) / 2
perimeter 24 so length + width half of that ie 12. Length 3 times width must be 9 and width 3.
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
The width of the rectangle would be 32.5 meters.
The perimeter of any rectangle is [ 2 x (length + width) ]. Since the length and width of a square are equal, the perimeter of a square is also [ 2 x (side + side) ] = (4 x side).
perimeter is the measure around the figure; area is the measure within the figure formula: perimeter: length+length+width+width=perimeter (for square or rectangle) area: length times width= area ( for square or rectangle)
Length: 4; Width: 5 or Length: 5; Width: 4
Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
Perimeter is 36 mArea is 72 square m
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
The perimeter of a rectangle whose length is 5cm wit a width of 6cm is 22cm
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.