It is important to mention what is the shape of object is.
If it is a right triangle, then the hypotenuse length (c) is defined by the equation
c2 = a2 + b2
c2 = (169) + (25) = 194
c = about 13.93
13
Height = sqrt(3)/2 * length of side So here, approx 4.3301 cm
* no, that would mean would of your side lengh's is larger than your whole shape
Such a pentagon is impossible. A regular pentagon, with side lengths of 26 m has a perimeter of 5*26 = 130 metres. Four sides of the irregular pentagon are 19.9 cm, 24.8 cm, 30 cm and 49.2 cm making a total of 123.9 cm. The length of the fifth side must be less than 123.9 cm. Therefore the perimeter of the irregular pentagon must be less than 247.8 cm - less than 2% of the required length of 130 metres or 13,000 cm.
It is: 6*5*5 = 150 square cm
The length of the hypotenuse of a right triangle with legs of lengths 5 and 12 units is: 13The length of a hypotenuse of a right triangle with legs with lengths of 5 and 12 is: 13
A regular pentagon is equilateral(all sides are equal) 5*13 = 65 cm
If a polygon with a perimeter of 30 centimeters has sides with length 6 cm/side, then it has 30 cm / 6 cm per side = 5 sides. So a regular pentagon with a side length of 6 cm has a perimeter of 30 centimeters.
2.5 cm. If the area of a pentagon is increased by 12.5 cm and each side of the pentagon is the same length, then each side would increase by 2.5 cm. (12.5 cm/ 5 sides = 2.5 cm/ side.
a line "a side" does not have an are because it is one-dimensional. A better question might be "what is the side length of a square that is 125 cm squared" In which case the side length would be the square root of 125 or 5*square root of 5.
20 cm/5 = 4 cm
~7.1 cm
The answer is 25cm², because you multiply 5 by 5.
A square that is 5 cm on each side is a perfect square. It is 25 cm in area which is found by multiplying the length of one side by the base. It's perimeter is the sum of its sides which is 4 x 5 cm = 20 cm.
There are an infinite number of different triangles that all have two sidesmeasuring 3cm and 5 cm.The third side can be any length between 2cm and 8 cm.
An octagon has eight sides, in this case all the same length. Total length of eight sides = 40 cm. Length of each side = 40 divided by 8 equals 5 cm
Perhaps surprisingly, it is 5 cm.
It seems that we have a triangle whose length sides are 21 cm and 5 cm. So that the third side would have a length which can be smaller than 21 + 5 = 26 cm, and bigger than 21 - 5 = 19 cm (19 cm < PR < 26 cm).Thus, all the numbers between 19 and 26 could be the length of the third side of the given triangle.