Without seeing the diagram your question (as originally written) was incomplete and impossible to answer.
If you had described your question (by rewriting it as I did) instead of blindly copying it, then the Answers community would have had all the necessary information to be able to answer your question and you would have got your homework done for you quicker. In fact, in rewriting the question you may actually have realised what was needed to be calculated and done it yourself - a very useful skill in being able to extract the required mathematics from the given information.
Anyway, what is now obvious from the rewritten question is you have is the cosine ratio:
cosine = adjacent/hypotenuse
→ cos F = FE / DF
→ DF = FE / cos F
As you didn't bother to give us the required information, I can't be bothered to fill in the numbers and calculate the required value - you can do that.
-----------------------------------------------------------------------------
What I was taught at pre-secondary school (some 40 odd years ago) to help remember the different trigonometric ratios:
In a right angle triangle there are three sides to an angle:
Opposite - the side opposite the angle
Adjacent - the side adjacent to the angle which is not the hypotenuse.
Hypotenuse - the side opposite the right angle
There are three ratios:
Tangent = Opposite / Adjacent
Sine = Opposite / Hypotenuse
Cosine = Adjacent / Hypotenuse
To remember them, use this nonsense rhyme:
Two Old Arabs
Soft Of Heart
Coshed Andy Hatchett
The initial letter of each word in each line gives the ratio:
Two Old Arabs → T = O / A → Tan = Opp / Adj
Soft Of Heart → S = O / H → Sin = Opp / Hyp
Coshed Andy Hatchett → C = A / H → Cos = Adj / Hyp
There is not enough information to answer the question. The question, as originally posted, did not specify that the triangle was right angled and you may not simply assume that DEF is right-angled. If you are willing to assume that then why not just assume that DF = 15.1 cm (or any number that you fancy) and be done with it!
The length of the hypotenuse of a right triangle with legs of lengths 5 and 12 units is: 13The length of a hypotenuse of a right triangle with legs with lengths of 5 and 12 is: 13
The length of a hypotenuse with the right triangle sides of 15 and 36 is: 39
That depends entirely on the LENGTH of the hypotenuse !
Find the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length.
In a 30-60-90 triangle, the hypotenuse is double the length of the shorter leg.
The hypotenuse measures 11.4 meters in length.
Using Pythagoras' theorem the length of the hypotenuse is 17.1 inches
Interior angles: 90 degrees, 53 degrees and 37 degrees Length of the hypotenuse: 8.75 cm
The median to the hypotenuse of a right triangle that is 12 inches in length is 6 inches.
The simplest answer, requiring no calculation, is that BC is the hypotenuse and so the length is 12 cm.
A right triangle with a hypotenuse of length 15 and a leg of length 8 has an area of: 50.75 units2
The hypotenuse of the nth triangle has a length of sqrt(n+1)
the length of the hypotenuse is 10.63
The length of the hypotenuse of a right triangle with legs of lengths 5 and 12 units is: 13The length of a hypotenuse of a right triangle with legs with lengths of 5 and 12 is: 13
The length of the hypotenuse would be approximately 24.41 and the angle, theta, would be approximately 35.
The length of a hypotenuse with the right triangle sides of 15 and 36 is: 39
9 The other two legs are 6.364 to the nearest thousandth