0.5
Let X represent the length, then X-4 represents the width. Perimeter of the rectangle is length plus width multiplied by two. Hence, 2(X + X - 4) = 100; 4X - 8 = 100; 4X = 108; X = 27. The length is 27 mm and the width is 27 - 4 = 23 mm. width = w length = w + 4 perimeter = w + w + w + 4 + w + 4 = 100 4w + 8 = 100 4w = 92 w = 23 width = 23 length = 27 area = 23 x 27 = 621
Since the length is greater than the width, any value greater than sqrt(43.7) which is approx 6.61 metres. For example, length = 40m, width = 43.7/40 m or length = 100m, width = 43.7/100 m or length = 1000000m, width = 43.7/1000000 m
2(2x) +2x = 100
Invalid conversion: square inches is a measure of area and inches is a measure of length or distance.If each side of a square is 10 inches long, the area of the square will be 100 square inches. (10*10=100)For any rectangle with an area of 100 square inches, the length of the short side times the length of the long side must total 100.(For instance, a rectangle 4 inches by 25 inches: 4*25=100)
area of rectangle = l * b area = 8 * 5 =40 m ^2 ( 1 m=100 cm 500cm= 5 m)
If the area is of a rectangle, it is simply the length times the width. If you have a rectangle with sides of 2 and 50 then the area is 100.
Assume the area of the rectangle is 70 squarecentimeters.Convert the length to centimeters : 1 meter = 100 cm : 10 meters = 1000 cmArea of a rectangle = length x width.70 = 1000 x width : width = 70/1000 = 0.07 cmPerimeter of a rectangle = 2 (length + width) = 2(1000 + 0.07) = 2 x 1000.07 = 2000.14 cm = 2000.14/100 = 20.0014 meters.
Area of square: 10*10 = 100 square m Area of rectangle: 14*10 = 140 square m
If you have the area you must have one other number, like the width of the field. So if the area of the field is 10,000 square feet, and the width is 100 feet, then divide the area by the width and you have the length. Area of a rectangle = length x width
The other length is 100 feet because 3*100 = 300.
Let X represent the length, then X-4 represents the width. Perimeter of the rectangle is length plus width multiplied by two. Hence, 2(X + X - 4) = 100; 4X - 8 = 100; 4X = 108; X = 27. The length is 27 mm and the width is 27 - 4 = 23 mm. width = w length = w + 4 perimeter = w + w + w + 4 + w + 4 = 100 4w + 8 = 100 4w = 92 w = 23 width = 23 length = 27 area = 23 x 27 = 621
30 ft
Length + width = half perimeter = 100". Length is 98", width is 2"
What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in
20
Width = Area/Length = 100/10 = 10 feet. Perimeter = 2*(L + W) = 2*(10 + 10)= 40 feet.
If you're talking about a rectangle, then the answer is 100. There are 2 sides that have 40 as the length, and double that length is 80. There are 2 sides that have 10 as the width, and double that width is 20. 80 + 20 = 100.