Assuming 96 refers to the area of therectangle, the answer is: infinite.
Consider the following sequence of rectangles with breadh B units and length L units.:
Breadth = 1 Length = 96. Area = 96, Perimeter = 194
B= 0.1, L = 960. A = 96, P = 1920.2
B = 0.01, L =9600. A = 96, P = 19200.02
B = 0.001, L = 96000. A = 96, P = 192000.002
There is no limit to how small B can get and therefore, how large P can get.
What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units
4 x 24
A square of side 22 has an area of 484. Rectangle 23 x 21 has an area of 483...
Length + width = half perimeter = 100". Length is 98", width is 2"
The perimeter of a rectangle is not sufficient to determine its length.
What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units
we have the formula to find perimeter of the rectangle i.e. perimeter = 2(l+b) where l = length b = breadth substitute l=96 and perimeter = 334,we get 334 = 2(96+b) 334/2=96+b, 167 = 96 + b b = 167-96 =71. b = breadth of the given rectangle is 71.
96
The maximum area for a rectangle of fixed perimeter is that of the square that can be formed with the given perimeter. 136/4 = 34, so that the side of such a square will be 34 and its area 342 = 1156.
100 cm2
4X24
Assuming you're talking about a rectangle, 452.
1024
what is the perimeter of the rectangle
2*(40 + 8) = 2*48 = 96 cm.
4 x 24
dont is answer