answersLogoWhite

0

The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees.

135 degrees

User Avatar

Wiki User

10y ago

Still curious? Ask our experts.

Chat with our AI personalities

ViviVivi
Your ride-or-die bestie who's seen you through every high and low.
Chat with Vivi
CoachCoach
Success isn't just about winning—it's about vision, patience, and playing the long game.
Chat with Coach
BeauBeau
You're doing better than you think!
Chat with Beau

Add your answer:

Earn +20 pts
Q: What is the measure of an interior angle of a stop sign?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Algebra

Area of a stop sign if the measure of a side is 10 inches?

a stop sign has eight sides. ten times eight is eighty, therefore the awenser is eighty inches


What is the perimeter of a stop sign if one side measures 12 inches?

Perimeter is total edge length. A stop sign has 8 sides, so 8"*12=96"■


Where can you find a octagon?

As a stop sign


What does a regular hexagon look like?

It looks like the shape of a STOP sign except that it has only six sides.


Is there a relationship between a polygon's number of sides and its number of vertices and angles?

For a regular polygon, all sides are equal and all angles are equal. Draw a regular hexagon. This website shows you an easy way to draw a hexagon with a compass. http://www.wikihow.com/Draw-a-HexagonDraw a line from one vertex to another going thru the center. This should make 2 identical triangles. Do this, until you have 6 triangles. Use a protractor to measure the 6 angles in the center and the base angles. They should each be 60º angles. Two of these adjacent base angles measure 120º. This is the vertex angle. There are 6 vertices, 6 sides, 6 - 60º angles in the center, and 6 - 120º angles at the 6 vertices.1. If a polygon has n sides, there will be n angles at the center, n vertices and n triangles.2. Draw the 5 lines connecting each vertex to the center of the polygon making 5 angles.There are 360º around the center point, so 360º ÷ n is the measure of each angle at the center.The angle of the triangle at the center of the polygon = 360 º ÷ n. This angle is the angle of the triangle at the center of the polygon.The sum of the interior angles in a triangle = 180ºThe sum of the 2 base angles of each triangle must be 180 º - (360 º÷ n).Each of the base angles of the triangle must measure (180º - (360 º÷ n)) ÷ 2.Two adjacent base triangles from adjacent triangles form a vertex angle, so the vertex angle = 2* (180º - (360 º÷ n)) ÷ 2.Two adjacent base angles = one vertex angle.The vertex angle = 2 * (180º - (360 º÷ n) ÷ 2, which means you do not have to divide by 2. You can stop at step #6.Now let's try a sample problem. Here is a site for constructing a pentagon. http://www.kjmaclean.com/Geometry/PentConstruct.htmlFind the relationship between a pentagon's number of sides and its number of vertices and angles? Since a penta means 5, a pentagon has 5 sides, 5 vertices, and 5 angles. Now let's find the vertex angle.Since a penta means 5, a pentagon has 5 sides, 5 vertices, and 5 angles.5 angles360º ÷ 5 = 72ºThe angle of the triangle at the center of the polygon = 72º72 º + nº + nº = 180º180 º - (360 º÷ 5) = 108ºEach of the base angles of the triangle must measure 108º ÷ 2 = 54 ºThe vertex angle = 2* 54 º = 108ºNotice that the answer to #6 and #8 are the same.