Since the 50-sided polygon is a regular polygon, then:
The sum of 50 angles = (50 - 2)(180⁰) = 48(180⁰) = 8,640⁰
Each angle measure = 8,640⁰/50 = 172.8⁰
10000000000000
51º per interior angle
How many sides does a regular polygon have if the measure of each interior angle is equal to 172 degress ?
Each interior angle measures 165.6 degrees
Each interior angle measures 170 degrees
Now, a 50-gon (the correct term is a pentacontagon, but that takes too long to type) has 50 sides. The equation for the interior angle of a regular polygon (we're talking about a regular 50-gon, right?) is [(n-1)*180]\n where n is the number of sides the polygon has. So in this case, the sum of the interior angles is 8820, and the measure of one angle is 176.4 degrees.
In a regular polygon, the measure of the exterior angle is related to the interior angle by the equation: exterior angle = 180° - interior angle. If the exterior angle is twice the measure of the interior angle, we can set up the equation: exterior angle = 2 × interior angle. Solving this gives us the equation: 180° - interior angle = 2 × interior angle, leading to 180° = 3 × interior angle, or interior angle = 60°. This corresponds to a regular hexagon, as it has interior angles of 120° and exterior angles of 60°.
Each interior angle will measure 162 degrees
Providing it's a regular polygon: 360/50 = 7.2 degrees
The measure of each interior angle of a fifteen sided regular polygon, a pendedecagon, is 156o.
It is: 180-exterior angle = interior angle because there are 180 degrees on a straight line
144
120°
135 Each interior angle of a regular octagon measures 135 degrees.
A regular trapezoid (!) is a square. And each interior angle of a square is 90 degrees.
Each interior angle of a regular 8 sided octagon measures 135 degrees
Each interior angle of a regular 9 sided nonagon measures 140 degrees