If your "53" is in degrees, then the vertex angle is 74 degrees.
That's an isosceles triangle.
The total internal angles of a triangle always equal 180 degrees. Therefore, the third angle of this triangle must be 180 - 54 - 63 = 63. Since this value is the same as one of the stated sides, the triangle is indeed isosceles.
An isosceles triangle has two equal angles and one different angle. The sum of the angles in any triangle is always 180 degrees. Therefore, the two equal angles in an isosceles triangle must add up to 180 degrees minus the different angle. So, each of the two equal angles in an isosceles triangle measures (180 - x) / 2 degrees.
The interior angles of a triangle add up to 180. So a triangle with 3 equal sides (or angles) will have 60-degree angles. * * * * * True, but the question is about an isosceles triangle, not an equilateral triangle. The angles of an isosceles triangle are x, x and 180-2x degree where x is a measure between 0 and 90 degrees.
64° is.
63
84 degrees
84 degrees
(180 - 38)/2 = 71 degrees (base angles of an isosceles triangle are congruent).
If a triangle is an isosceles triangle as well as being a right-angled triangle, the size of the two angles (that are not right angles) are 45 degrees.
You are an isosceles triangle.
It is an isosceles triangle
In all triangles, the angles always measure up 180 degrees. In an isosceles triangle two of the angles are equal.
The vertex angle of an isosceles triangle is equal to the measure of each of its base angles. Therefore, if one of the base angles measures 42 degrees, then the vertex angle also measures 42 degrees.
40 degrees each
63 degrees
It is possible if neither of the angles in the triangle measures to 60 degrees