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If d is the distance between them, then
d2 = (-6 -10)2 + (1 - (-8))2 = (-16)2 + 92 =256 + 81 = 337
so d = sqrt(337) = 18.36
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∙ 14y ago
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Find the distance between the points -2 -10 and 10 6?
The sq.root of 122+162=20
Find the distance between the points -10 8 and -2 -7?
Use Pythagoras' Theorem: calculate the square root of ((difference of x-coordinates)2 + (difference of y-coordinates)2).
What is the distance between the points 22 27and 2 -10?
square root of ((22 -2)^2 + (27 +10)^2) = square root of (400 + 1369) which is equal to square root of (1769) = 42.05948169
What is linear scale?
A scale where the distance between 1 and 2 is the same as the distance between 2 and 3; and so on. By way of contrast, in a logarithmic scale, the distance between 1 and 10 would be the same as the distance between 10 and 100, or 100 and 1000. There are many other scales.
A flagpole stands 30 feet above the ground. The base of the flagpole reaches 10 feet into the ground. What is the vertical distance between the highest and lowest points of the flag pole?
40
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If the points are (3, 2) and (9, 10) then the distance works out as 10
Find the distance between the points-2 -10 and -8 -2?
10
Find the distance between the points -2 -10 and 10 6?
The sq.root of 122+162=20
Find the distance between the points A 9 3 and B 15 11?
10
What is the distance between the points (45) and (1013) on a coordinate plane?
If you mean points of (4, 5) and (10, 13) then the distance works out as 10
What is the distance between the points (22) and (8-6)?
Points: (2, 2) and (8, -6) Distance: 10
What is the distance between the points (10 12) and (4 36)?
The distance between points can be calculated using Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((4 - 10)² + (36 - 12)²) → distance = √((-6)² + (24)²) → distance = √(36 + 576) → distance = √612 → distance = 6 √17 ≈ 24.74 units.
What is the distance between the points -6-10 and 25?
If you mean points of: (-6, -10) and (2, 5) then it works out as 17
What is the distance between the points (4 5) and (10 13) on a coordinate plane?
10 units
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(-10--2)2+(8--7)2 = 289 and the square root of this is 17 Therefore the distance is 17 units in length.
What is the distance between the points (45) and (103) on a coordinate plane?
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Find the distance between the points -2 -10 and -8 -2?
The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (-6) and a vertical distance y2-y1 (8). The square root of the squares is sqrt [62 + 82] = sqrt [100] = 10.
