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The sequence given is an arithmetic sequence, where each term is obtained by adding a fixed difference to the previous term. The difference between consecutive terms is increasing by 3 each time (3, 5, 7, 9). To find the nth term of this sequence, we can use the formula for the nth term of an arithmetic sequence: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the position of the term, and (d) is the common difference. In this case, the first term is 6 and the common difference is increasing by 3 each time. So, the nth term for this sequence is (6 + (n-1)3), which simplifies to (3n + 3).
Oh, isn't that just a beautiful sequence of numbers? To find the pattern, we can see that each number is increasing by adding consecutive odd numbers: 3, 5, 7, 9. So, to find the nth term, we can use the formula n^2 + 5.
n squared + 5
n^2 + 5
N squared +5
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What is the formula for the nth term for the sequence 12-21-30-39-48?
> since the value rises by nine at each step and the first term is 12 the formula for > the nth term is: 12+(n-1)*9 Which simplifies to Sn = 9n + 3
If the nth term of a sequence is 12n-6 what is the 8th term?
90
What is the nth term for 3 10 17 24 31?
You can see that all the numbers go up by 7. This means that the first part of the nth term rule for this sequence is 7n. Now, you have to find out how to get from 7 to 3, 14 to 10, 21 to 17 ... this is because we are going up in the 7 times table. To get from the seventh times table to the sequence, you take away four. So the answer is : 7n-4
What is the nth term of 2 9 16 23 30?
The nth term is 7n-5 and so the 6th term will be 37
How do you find the 30th term if nth term is 3n-1?
Just plug in 30 for n in 3n-1. The answer is 89.
Why is the nth term n2 5 if the sequence is 6 9 14 21 30?
Clearly here the nth term isn't n25.
What is the nth term 4 14 30 52 80?
t(n) = 3n2 + n = n(3n + 1)
What is the nth term if the sequence goes 12 21 30 39 48?
Looks like 57: 12+9=21, +9=30, +9=39, +9=48, +9=57.
What is the formula for the nth term of this sequence 14 22 30 38 46?
Oh, dude, you're hitting me with the math questions, huh? So, the formula for finding the nth term of an arithmetic sequence is a + (n-1)d, where a is the first term and d is the common difference. In this sequence, the common difference is 8 (because each term increases by 8), and the first term is 14. So, the formula for the nth term would be 14 + 8(n-1). You're welcome.
What is the formula for the nth term for the sequence 12-21-30-39-48?
> since the value rises by nine at each step and the first term is 12 the formula for > the nth term is: 12+(n-1)*9 Which simplifies to Sn = 9n + 3
If the nth term of a sequence is 12n-6 what is the 8th term?
90
What is nth term for sequence 30 27 24 21?
There are infinitely many possible answers. But the simplest is Un = 33 - 3n for n = 1, 2, 3, ...
What is the nth term for 3 10 17 24 31?
You can see that all the numbers go up by 7. This means that the first part of the nth term rule for this sequence is 7n. Now, you have to find out how to get from 7 to 3, 14 to 10, 21 to 17 ... this is because we are going up in the 7 times table. To get from the seventh times table to the sequence, you take away four. So the answer is : 7n-4
What is nth term of this sequence 16 22 30 40?
6n+10
What is the 30th term of the sequence when the nth term is 3n-1?
When n=30, 3n-1 = 89 .
What is the nth term of 2 9 16 23 30?
The nth term is 7n-5 and so the 6th term will be 37
How do you find the 30th term if nth term is 3n-1?
Just plug in 30 for n in 3n-1. The answer is 89.
