The pOH is the negative log of the OH- concentration. Thus, pOH = -log 2.0x10^-2pOH = 1.699 = 1.7
Fe3+ + 3OH- _____> Fe(OH)3
It is a linear equation in one variable, x. Oh, I suppose you want the solution? 2x + 33 = 4x + 11 Subtract 2x from both sides: 33 = 2x +11 Subtract 11 from both sides: 22 = 2x Divide both sides by 2: 11 = x
[ch3nh3+][oh-] / [ch3nh2]
Nh3 + h2o-----> nh4oh ----->(nh4)^+ + (oh)^-
Oh, and I mean A+B+C=BB
1.70
12.85 is the pOH.
1.70
[OH-] = 3.31 log[OH-] = pOH = .51982 14-pOH = pH = 13.48
1.70
The pOH is 6,4.
pH and pOH are a measure of the concentration of the hydronium ions and hydroxyl ions respectively in the solution. pH = -log[H+] pOH = -log[OH-] and they are related: pH + pOH = 14
12.85
12.85
1.70
1.70
12.85