In order to make sense of this question it is necessary to assume that the area is 28 SQUARE metres and not 28 metres as stated.
Then,
Length = Area/Width = 28/4 = 7m
Then perimeter = 2*(Length + width) = 2*(7 + 4) = 2*11 = 22 metres.
Rectangle with area 28 m2 and width = 4 m => length = 28/4 = 7m. Then, perimeter = 2*(4+7) = 2*11 = 22 metres.
One side will be 28/4 = 7m
Let ABCD be the border of square garden of side 30m and the shaded region be the path Then AD = 30m , XP=1m, SY = 1m and XY = AD ⇒ XP + PS + SY = AD ⇒ PS = AD - XP - SY = 30m - 1m - 1m = 28m ∴ PQRS in a square of side 28m ∴ The area of path = Area of ABCD - Area of PQRS
Rectangle with area 28 m2 and width = 4 m => length = 28/4 = 7m. Then, perimeter = 2*(4+7) = 2*11 = 22 metres.
To fence an area is equivalent to finding its perimeter. Since the area of a square = length*width, it must be that the square root of its area is the length of a side, which is sqrt(28). Since there are four sides in a square, the perimeter is equal to 4sqrt(28) = 21.66m I'm sure the question states that the square's side (not area) is 28 metres. In that case, perimeter = 4*28 = 112 metres.
it is 54m length ways and 28m width
One side will be 28/4 = 7m
easy 28m
28m
A circle with a radius of 14 meters has an area of 615.75 square meters.
16m-28m factored = -12
Assuming that radious refers to radius, the volume is 19792 cunic units.
7m
The measurement of 29m mean the measurement of 29m which is 1 more than 28m.
.28m