The answer will depend on what measure of the semicircle is 5 inches: its radius or diameter.
Perimeter:20 inches Area:35
dot know ..... just tell me the answer stupid computer
That depends on what you mean by a "20 ft semicircle".A semi-circle is a half circle.A 20 ft circle could be:A circle of diameter 20 ftThe perimeter of the semicircle is half the circumference plus the diameter → perimeter = 1/2π 20 ft + 20 ft= 10π + 20 ft≈ 51.42 ftA circle of radius 20 ftThe perimeter of the semicircle is half the circumference plus double the radius → perimeter = 1/2 2π 20 ft + 2 x 20 ft= 20π + 40 ft≈ 102.08 ftA circle of circumference 20 ftThe perimeter of the semicircle is half the circumference plus the diameter → perimeter = 1/2 20 ft + 20 ft ÷ π= 10 ft + 20/π ft≈ 16.37 ftHowever, if a 20 ft circle is a circle with a circumference (= perimeter) of 20 ft then a 20 ft semi-circle could be a semicircle with a perimeter of 20 ft→ perimeter = 20 ft
8*pi + 16 = 41.13 cm (approx)It depends on whether 8 cm is the radius or diameter of the semicircle.
The area of a square whose perimeter is 36 inches is: 81 square inches.
To find the perimeter of a semicircular region with a diameter of 5 inches, you first calculate the radius, which is 2.5 inches. The circumference of a full circle is given by (C = 2\pi r), so for the semicircle, it is (\pi r). Thus, the perimeter of the semicircle is (\pi \times 2.5) inches plus the diameter, which is (2.5\pi + 5) inches. Therefore, the total perimeter is approximately (2.5\pi + 5 \approx 7.85 + 5 = 12.85) inches.
92.55 inches
The circumference of a circle = 2π r = π a (where a is the base of the semicircle and is also the diameter of the circle) The perimeter of the semicircle = half the perimeter of the circle + the base length The perimeter of the semicircle = πa/2 + a = a(1 + π /2) feet
To find the perimeter of the curved section of the semi-circle: Perimeter of semicircle = Pi x radius If you also need to the find the perimeter of the straight part of the semicircle (the diameter), it is simply double the radius.
Perimeter = (2*pi*5*1/2)+10+16+16 = 57.70796327 or 58 feet
The perimeter of a semicircle with radius R is pi*R + 2*R = R*(pi + 2)
The perimeter of the semicircle is 71.98 inches, approx. The semicircle cannot be covered by any number of inches because an area (in 2-dimensional space) cannot be covered by a length (in 1-dimensional space).
The circumference of a circle is 2{pi}r. So, for a semicircle it is half this, that is {pi}r. The perimeter of the semicircle is the round bit ({pi}r) plus a diameter of the circle (2r) perimeter = {pi}4 + 2 x 4 ~= 20.6 in Area of a circle is {pi}r2, so for a semicircle it is half this. area ={pi}42 / 2 ~= 25.1 in2.
Perimeter of a semicircle is the length of the half-circle plus the diameter. The whole circle would have a length of diameter times pi, but since it's only half... Perimeter of semicircle = (1/2*pi*D) + D
The perimeter is 11 + 5 + 13 = 29 inches.
The perimeter of each pentagon is 25 inches.
A semicircle is half a circle. So the perimeter of a semicircle is half the circumference of the whole circle plus the diameter, which is twice the radius: perimeter = 1/2 x 2{pi}r + 2r perimeter ~= 3.14x8 + 2x8 ~= 41.13cm