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What is the point of contact when the circles x2 plus y2 -6x plus 8y -75 equals 0 and x2 plus y2 -30x -24y plus 269 equals 0 touch each other?
Wiki User
∙ 6y ago
1st circle: x^2 +y^2 -6x +8y -75 = 0
1st circle: center at (3, -4) and radius 10
2nd circle: x^2 +y^2 -30x -24y +269 = 0
2nd circle: center at (15, 12) and radius 10
Midpoint of (15, 12) and (3, -4): (9, 4) which is the point of contact
Proof: distance from (15, 12) to (9, 4) = 10
Proof: distance from (3, -4) to (9, 4) = 10
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoIt is (9, 4)
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