1st circle: x^2 +y^2 -6x +8y -75 = 0
1st circle: center at (3, -4) and radius 10
2nd circle: x^2 +y^2 -30x -24y +269 = 0
2nd circle: center at (15, 12) and radius 10
Midpoint of (15, 12) and (3, -4): (9, 4) which is the point of contact
Proof: distance from (15, 12) to (9, 4) = 10
Proof: distance from (3, -4) to (9, 4) = 10
-2
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
16.1
it equals 0.000010 because the negative means the decimal point moves 6 spaces to the left
(2, -2)
The centres and the point of contact are all in a straight line, if the circle is inside or outside.
If the two circles are tangent to each other,then it must be at the same point.
Yes, circles that share one and only one point are tangent to each other.
Concentric circles are the circles with the same center therefore they do not cross with each other as the "center is not considered a point on the circle". An exception would be two circles that are concentric and have the same radius, in which case the circles are indistinct and every point of the circles is an intersection.
Concentric circles are circles that share the same center point, with each circle surrounding the other. Eccentric circles, on the other hand, do not share the same center point and are offset from each other. In simpler terms, concentric circles are like a target with multiple rings around a common center, while eccentric circles are like two circles that are not aligned at the same center point.
No; tangent circles touch each other at one point but concentric circles cannot not touch.
Combine the equations together and using the quadratic equation formula it works out that the point of contact is at (5/8, 5/2)
Concentric circles
Tangential circles.
there used in powerpoints and other presentations to highlight key points. See the filled in the circles below * point A * Point b * Point C
-2
When the centers of both the circles are at the same point.