24 (mol/L)s
.72
Yes, but it is customary to express it as 2 seconds per foot. The denominator - or second measure - usually takes the value 1 in a unit rate.
The first responder posted this response:$1,280.08====================================The next responder posted this response:Assuming the 5% interest rate is the nominal annual rate, the first step is to calculate the effective interest rate.ieffective = (1+r/m)m - 1where r is the nominal rate (.05) and m is the compounding periods per year (semiannual = 2 compoundings per year).ieffective = (1+.05/2)2 - 1 = .0506Simply use this effective rate to solveFuture Value = Present Value * (1+i)nwhere i is the effective interest rate and n is the number of years.F = 1000*(1+.0506)5 = $1280.08
2x - 4 = 12Add 4 to each side:2x = 16Divide each side by 2:x = 8
The expression "8x for each value of x" means that you are multiplying the value of x by 8. This indicates that for every possible value of x, you will multiply that value by 8. For example, if x is 2, then 8 multiplied by 2 equals 16. This expression represents a linear relationship where the output is 8 times the input value of x.
The rate of the reaction is determined by the rate law, which is typically expressed as Rate = k[A]^m[B]^n, where m and n are the orders of the reactants. If k = 3, A = 2 M, and B = 2 M, and the reaction is kA^2B, then the rate would be 3 x (2)^2 x (2) = 24 M/s.
If the concentration of H2 were halved, the rate of the reaction would also be halved, assuming H2 is part of the rate-determining step. The rate law rate = k[NO2][H2] shows that the rate is directly proportional to the concentration of H2.
If the rate law for the reaction is given by rate = k[A]^m[B]^n, where m and n are the orders of the reactants A and B, respectively, then the rate of the reaction would be calculated as rate = k[A][B]. Plugging in the values given (k = 3, A = 2M, B = 2M), the rate of the reaction would be 3*(2)*(2) = 12 M/s.
The rate of a reaction can be determined using the rate law expression, which involves the rate constant (k) and the concentrations of reactants (A and B). Without knowing the specific form of the rate law, we cannot calculate the rate based solely on the values of the concentrations A and B. Additional information about the rate law or the order of the reaction with respect to A and B would be needed.
.72
The rate of the reaction is calculated using the rate equation: rate = k[A]^3[B]^2. Given k = 0.01, [A] = 2 M, and [B] = 3 M, the rate can be determined by substituting these values into the rate equation and solving for the rate.
The overall reaction order for the rate law rate = k[A]^2[B][C] is 4, which is calculated by summing the individual reaction orders for each reactant ([A]^2 has an order of 2, [B] has an order of 1, [C] has an order of 1).
.72 (mol/L)/s
0.4 (mol/L)/s
7.4 10-3
Halving the concentration of H2 will decrease the rate of the reaction, assuming it is a first-order reaction with respect to H2. Since the rate law is rate = k[NO]^2[H2], cutting the concentration of H2 in half will decrease the rate of the reaction by a factor of 0.5.
It is multiplied by 2 if the intermediate reaction is multiplied by 2