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What is the rate of a reaction if the value of k is 0.1 A is 1 M and B is 2 M?
Wiki User
∙ 11y ago
Verified answer
0.4 (mol/L)/s
Wiki User
∙ 11y ago
Dilim
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A trapezoid has no intrinsic value.
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\3
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Since the reaction is first order with respect to H2, if the concentration of H2 were halved, the rate of the reaction would be halved. This can be seen by entering one for each value in the rate equation, then changing the value of [H2] to 1/2 while keeping the other values the same: The rate changes from 1 to 1/2.
What is The order of reaction for which unit of rate and rate constant is same?
In a zero order overall process, the rate and rate constant will be the same. (Reaction order is an exponent, and if that exponent is "0" then the value is "1" and will cancel out.)
Is 01 wrote out in percent as 01 percent?
No, 0.01 is not written as 0.01% in percent rate. 0.01 in percent rate is 1%.
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What is a 1.5 order of reaction?
A + B --> C has non-elementary reaction rate equation -rA = kCACB1/2 The exponent of CA is 1, the exponent of CB is 1/2, for an overall reaction order of 1 + (1/2) = 1.5. Do not let the stoichiometric coefficients from the reaction mislead you. It has to do with the rate equation for a given reaction, not the (net) chemical reaction itself.
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1. The rate of forward reaction = to the rate of backward reaction. 2. Concentration of the substance are constant.
What is the overall reaction order for this rate law rate equals kA2BC?
The overall reaction order for k[A]^2[B][C] would be 4 Because [A] has a rate order of 2 [B] has a rate order of 1 [C] has a rate order of 1 And when you add them together... 2 + 1 + 1 You obtain four
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What is the ratio between the two?
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equilibrium means the rate of forward reaction = rate of backward reaction... there are three types of equilibrium 1. amount of products > amount of reactants 2. amount of products = amount of reactants 3. amount of products < amount of reactants
When the concentration of a reactant was 0.100 M the rate of the reaction was 8.42 X 106 M s-1 When the concentration of the reactant was doubled to 0.200 M the rate increased to 1.59 X 105 M s1 What?
What indeed. Your "increased" rate has a lower value than your initial rate.
