It is (-3, 5).
S' = (3, -2) B' = (0, -1) C' = (3, -4).
the z axis is at right angles to both the x and the y axis. All 3 axis pass through the origin.
The image is (-5, 3)
It depends on the number of variables and their nature: 2 variables, both independent: either axis 2 variables, one independent: x-axis 3 variables, all independent: any axis 3 variables, 2 independent: x or y-axis. 3 variables, 1 independent: x-axis. and so on.
It is (-3, 5).
Each reflection produces a mirror image.=================================Answer #2:With the initial point at (0, 0) ... the origin of coordinates ...-- the first reflection, across x = -3, moves the point to (-6, 0), and-- the second reflection, around y = -3, moves it to (-6, -6) .
S' = (3, -2) B' = (0, -1) C' = (3, -4).
It is (-3, 5).
The answer will depend on the original coordinates of A: these have not been provided so neither has an answer.
It will be (-2, 3, -5).
-1,3
The image of point P(2, 3, 5) after a reflection about the xy-plane is P'(2, 3, -5). This means that the x and y coordinates remain the same, but the z coordinate is negated.
you graph at the (3) point on the y axis. it should look like a vertical line across the y axis on where it says 3
7
(3,-8)
Oh, dude, you can use transformations like translations, rotations of 180 degrees, or a combination of reflections across the diagonal or perpendicular bisectors to carry the rectangle ABCD onto itself. It's like playing Tetris but with shapes, you know? So, yeah, those are the moves you can make to keep the rectangle where it belongs.