Oh, dude, the side included between angles M and N of triangle MNP is MN. Like, it's the side that's actually between those two angles, you know? So, if you're ever at a party and someone asks you that, you can be like, "Oh, it's MN, no big deal."
Converse of the Hinge Theorem:If tow sides of one triangle are congruent to two sides of another triangle and the the included angles are not congruent, then the included angle that is larger has the longer third side across from it.
-48
False
False.
Incorrect. The relationships between the angles inside a triangle will be identical to the relationships between the lengths of the sides opposite those angles. For example, take any scalene triangle with the corners A, B, and C. If ∠A is the widest angle, ∠B is the mid-range, and ∠C is the smallest, then B→C will be the longest side, A→C will be the mid-range side, and A→B will be the shortest side.
If two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent.
SAS
Yes. What about them?
If two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, then the two triangles are congruent.
There are several methods to prove two triangles congruent, including: SSS (Side-Side-Side): All three sides of one triangle are equal to the three sides of another triangle. SAS (Side-Angle-Side): Two sides and the included angle of one triangle are equal to two sides and the included angle of another triangle. ASA (Angle-Side-Angle): Two angles and the included side of one triangle are equal to two angles and the included side of another triangle. AAS (Angle-Angle-Side): Two angles and a non-included side of one triangle are equal to two angles and the corresponding non-included side of another triangle. These methods are used to establish that two triangles are congruent, meaning they have the same size and shape.
To show that triangle ABC is congruent to triangle XYZ by the ASA (Angle-Side-Angle) criterion, we need to establish that two angles in triangle ABC are congruent to two angles in triangle XYZ, along with the side that is included between those angles being congruent. Specifically, if we have ∠A ≅ ∠X, ∠B ≅ ∠Y, and side AB ≅ XY, then the triangles can be concluded as congruent by ASA. Thus, we would need to confirm the congruence of these angles and the included side.
The Angle Side Angle postulate( ASA) states that if two angles and the included angle of one triangle are congruent to two angles and the included side of another triangle, then these two triangles are congruent.
(1) corresponding, (2) congruent
Yes, if two angles and a non-included side of one triangle are congruent to the corresponding two angles and side of another triangle, then the triangles are congruent by the Angle-Angle-Side (AAS) postulate. This postulate states that if two angles and a side that is not between them are congruent in two triangles, the triangles must be identical in shape and size. Therefore, the triangles are congruent.
Yes, they are.
If two angles and a non-included side of one triangle are congruent to the corresponding two angles and side of another triangle, the triangles are congruent by the Angle-Angle-Side (AAS) theorem. This theorem states that if two angles and a corresponding side of one triangle are equal to two angles and the corresponding side of another triangle, then the two triangles are congruent. Thus, the triangles will have the same shape and size.
To show that triangle JKL is congruent to triangle MNO by the Angle-Angle-Side (AAS) theorem, you need to establish that two angles and the non-included side of triangle JKL are congruent to two angles and the corresponding non-included side of triangle MNO. Specifically, you would need to verify that one of the angles in triangle JKL is congruent to one of the angles in triangle MNO, and that the side opposite the angle in triangle JKL is congruent to the corresponding side in triangle MNO. This would complete the necessary conditions for AAS congruence.