If you mean: slope of -13 and point of (5, 7) then the equation is y = -13x+72
1-13/16"
If you mean points of (3, 9) and (1, 3) then the slope is 3
First we note that the slope does exist between the two points because the two points do not have the same x co-ordinate. Next, we apply the slope formula. slope=(y2-y1)/(x2-x1) Note that it does not matter which point you call as 1 or 2, you will still get the same result. For this example we will call point (-5,-13) as point 1 and (-17,-19) as point 2. Therefore: slope=(-19-(-13)) / (-17-(-5)) = (-6) / (-12) = 1/2 Therefore, the slope of the line containing the points (-5,-13) and (-17,-19) is 1/2.
If you mean: (2, 13) and (-4, -11) then the slope is 4 and both equations will have the same slope of 4 but with different y intercepts
Parallel lines have the same slope. The slope of the second line is also 13.
59
It is 13/46.
33
If you mean points of (-3, 6) and (4, 6) then it works out that the slope is 0
A perpendicular lines slope is always the negative or opposite reciprocal of a lines slope. Therefore, if your slope is -13/1 then the perpendicularity of the other line is 1/13. The 13 would change positive there fore its its already a negative number then change it posiive.
If we call the slope m we can say that the slope of the perpendicular line is -1/m In this case as the slope, m, is 13 the slope of the perpendicular is -1/13 or -0.07692307692
Slope: -13 Point: (5, 7) Equation: y = -13x+72 whereas -13 is the slope and 72 is the y intercept
Slope: -13 Point: (5, 7) Equation: y = -13x+72 whereas -13 is the slope and 72 is the y intercept
-24
Points: (1, 4) and (4, 6) Slope: 2/3
The LCM is 598. 13*46=598